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First projections are measurable and square-integrable
Statement
For the setup of Two-sample order-r U-statistic and first projections, suppose . Then the section integrals defining and are finite and measurable almost everywhere, can be assigned measurable values on exceptional null sets, and define square-integrable centered projections. In particular,
Facts & Assumptions
Given: Probability measures , a product-measurable kernel with finite second moment under , and the projection definitions.
Two-sample order-r U-statistic and first projections defines and as the corresponding conditional section integrals minus .
Fubini's theorem for L^1 functions on a sigma-finite product gives integrable sections almost everywhere, measurable section-integral versions, and equality of iterated and product integrals.
Cauchy-Schwarz inequality for gives .
The product sigma-algebra and its finite iterates supplies the finite product sigma-algebras on which the section maps and product integrals are defined.
Proof
Given: and the definitions in [F1]. Prove both projections are measurable, centered, and square-integrable with the displayed bounds.
The product measure is a probability measure, so applying [F3] to and the constant function gives . Thus is integrable and is finite.
By [F4], the product decomposition uses the stated finite product sigma-algebra. Apply [F2] with first coordinate -distributed and the remaining coordinates distributed according to or . For -almost every , the section integral is finite; [F2] supplies a measurable version after setting it to zero on the exceptional null set. Reordering the coordinates and using the section gives a finite measurable for -almost every .
For each good , Cauchy–Schwarz [F3] on the remaining probability product measure gives . Integrating in and using [F2] yields . The same argument for the section gives .
By [F2], and . Subtracting this finite mean gives the centered projections in [F1]; step 2.1 and finiteness of show both remain square-integrable.
Depends on
Used by
- The weak null does not center every mixed kernel assignment Counterexample
- Pooled-mixture projection and variance Lemma
- Two-sample Hoeffding decomposition Lemma
- Permutation CLT for a two-sample U-statistic under a weak null Theorem
Cited to discharge well-definedness by Two-sample order-r U-statistic and first projections.
Dependency tree · two levels
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Sources
- Péter Major, Some Results About U-statistics, in On the Estimation of Multiple Random Integrals and U-Statistics, Lecture Notes in Mathematics 2079, Theorem 9.1 and proof (standard reference, not scraped)
- E. Y. Chung and J. P. Romano, Asymptotically Valid and Exact Permutation Tests Based on Two-Sample U-Statistics, Stanford Technical Report 2011-09, §3 (standard reference, not scraped)