Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

First projections are measurable and square-integrable

Statement

For the setup of Two-sample order-r U-statistic and first projections, suppose h∈L2(P⊗r⊗Q⊗r). Then the section integrals defining gX and gY are finite and measurable almost everywhere, can be assigned measurable values on exceptional null sets, and define square-integrable centered projections. In particular, EP[gX(X1)]=EQ[gY(Y1)]=0, EP[gX(X1)2]≤EP⊗r⊗Q⊗r[h2],EQ[gY(Y1)2]≤EP⊗r⊗Q⊗r[h2].

Facts & Assumptions

Given: Probability measures P,Q, a product-measurable kernel h with finite second moment under P⊗r⊗Q⊗r, and the projection definitions.

[F1]

Two-sample order-r U-statistic and first projections defines gX and gY as the corresponding conditional section integrals minus θ(P,Q;h).

[F2]

Fubini's theorem for L^1 functions on a sigma-finite product gives integrable sections almost everywhere, measurable section-integral versions, and equality of iterated and product integrals.

[F3]

Cauchy-Schwarz inequality for L2 gives ∣∫ab∣≤∥a∥2∥b∥2.

[F4]

The product sigma-algebra and its finite iterates supplies the finite product sigma-algebras on which the section maps and product integrals are defined.

Proof

Given: h∈L2(P⊗r⊗Q⊗r) and the definitions in [F1]. Prove both projections are measurable, centered, and square-integrable with the displayed bounds.

1.1F1F3

The product measure is a probability measure, so applying [F3] to h and the constant function 1 gives E∣h∣≤(Eh2)1/2<∞. Thus h is integrable and θ(P,Q;h)=Eh is finite.

1.2F1F2F4

By [F4], the product decomposition uses the stated finite product sigma-algebra. Apply [F2] with first coordinate P-distributed and the remaining 2r−1 coordinates distributed according to P or Q. For P-almost every x, the section integral fX(x)=∫h(x,x2,…,xr;y1,…,yr) dPr−1dQr is finite; [F2] supplies a measurable version after setting it to zero on the exceptional null set. Reordering the coordinates and using the Y1 section gives a finite measurable fY for Q-almost every y.

2.1F2F3step 1.2

For each good x, Cauchy–Schwarz [F3] on the remaining probability product measure gives ∣fX(x)∣2≤∫h(x,x2,…,xr;y1,…,yr)2 dPr−1dQr. Integrating in P and using [F2] yields EP[fX(X1)2]≤E[h2]. The same argument for the Y1 section gives EQ[fY(Y1)2]≤E[h2].

3.1F1F2step 1.1step 2.1∎

By [F2], EPfX=Eh=θ(P,Q;h) and EQfY=Eh=θ(P,Q;h). Subtracting this finite mean gives the centered projections in [F1]; step 2.1 and finiteness of θ show both remain square-integrable.

Depends on

Used by

Cited to discharge well-definedness by Two-sample order-r U-statistic and first projections.

Dependency tree · two levels

20 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources