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A quotient by a Weierstrass polynomial is a finite module over the smaller germ ring
Statement
Let be a Weierstrass polynomial of degree in . Then the quotient is a finitely generated -module, where when , generated by the residue classes of
Facts & Assumptions
Given: A degree- Weierstrass polynomial .
A Weierstrass polynomial is the monic degree- polynomial in the last variable from Weierstrass polynomials in the last variable.
Weierstrass division gives unique quotient and remainder of degree upon division by (Weierstrass division theorem).
Noetherian-module language is that of Noetherian commutative rings and modules.
Proof
By [L1] and [L2], every germ can be written uniquely as with . Modulo this becomes so the listed residue classes generate the quotient as an -module.
The same division theorem [L2] makes the remainder unique, so those generators give a canonical normal form for every class in the quotient. Since there are only generators, the quotient is a finite -module.
Depends on
Used by
Dependency tree · two levels
14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Jiří Lebl, Tasty Bits of Several Complex Variables, Section 6.4 (standard reference, not scraped)
- Jaap Korevaar and Jan Wiegerinck, Several Complex Variables, Section 4.5 (standard reference, not scraped)