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The simple integral is independent of the chosen representation
Statement
If a nonnegative simple measurable function admits two representations then the two coefficient sums defining are equal. So The integral of a nonnegative simple function is well defined.
Facts & Assumptions
Given: Two simple representations of the same nonnegative simple measurable function .
The simple integral is defined by with the convention (The integral of a nonnegative simple function).
A measure is countably additive on pairwise disjoint measurable families, hence finitely additive on finite measurable partitions (Measures on sigma-algebras).
Proof
For each pair put . The family is [given, L2] measurable and pairwise disjoint, and Whenever , the two simple formulas for agree on , so .
Finite additivity over the partitions in step 1.1 gives[step 1.1, L1, L2, algebra] If some coefficient is on a cell of infinite measure, the convention in [L1] forces both corresponding terms to be , so no ambiguity occurs there either.
Therefore the simple integral does not depend on the chosen representation, [step 2.1, L1] ∎ and the definition in [L1] is well defined.
Depends on
Used by
- The nonnegative integral agrees with the simple integral on simple functions Proposition
- The simple integral is monotone, homogeneous, and additive Proposition
Cited to discharge well-definedness by The integral of a nonnegative simple function.
Dependency tree · two levels
6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- John K. Hunter, Measure Theory Notes, Definition 4.1 (standard reference, not scraped)
- Gerald B. Folland, Real Analysis, 2nd ed., §2.2 (standard reference, not scraped)