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LemmaStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-27
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The simple integral is independent of the chosen representation

Statement

If a nonnegative simple measurable function s admits two representations s=i=1mciχEi=j=1ndjχFj, then the two coefficient sums defining sdμ are equal. So The integral of a nonnegative simple function is well defined.

Facts & Assumptions

Given: Two simple representations of the same nonnegative simple measurable function s.

[L1]

The simple integral is defined by sdμ=cjμ(Ej) with the convention 0(+)=0 (The integral of a nonnegative simple function).

[L2]

A measure is countably additive on pairwise disjoint measurable families, hence finitely additive on finite measurable partitions (Measures on sigma-algebras).

Proof

technique · direct
1.1

For each pair (i,j) put Gij:=EiFj. The family (Gij) is [given, L2] measurable and pairwise disjoint, and Ei=jGij,Fj=iGij. Whenever Gij, the two simple formulas for s agree on Gij, so ci=dj.

2.1

Finite additivity over the partitions in step 1.1 gives[step 1.1, L1, L2, algebra] iciμ(Ei)=i,jciμ(Gij)=i,jdjμ(Gij)=jdjμ(Fj). If some coefficient is 0 on a cell of infinite measure, the convention in [L1] forces both corresponding terms to be 0, so no ambiguity occurs there either.

3.1

Therefore the simple integral does not depend on the chosen representation, [step 2.1, L1] ∎ and the definition in [L1] is well defined.

Depends on

Used by

Cited to discharge well-definedness by The integral of a nonnegative simple function.

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources