Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-27
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The indefinite integral of a nonnegative simple function is a measure

Statement

Let s be a nonnegative simple measurable function on (X,A,μ) and define νs(A):=Asdμ(AA). Then νs is a measure on (X,A).

Facts & Assumptions

Given: A nonnegative simple measurable function s on (X,A,μ).

[L1]

For measurable A, the set function AAsdμ is defined as AsχAdμ (Integral over a measurable subset).

[L2]

The simple integral is additive and homogeneous on nonnegative simple functions (The simple integral is monotone, homogeneous, and additive).

[L3]

A measure is a set function with value 0 at the empty set and countable additivity on pairwise disjoint measurable families (Measures on sigma-algebras).

Proof

technique · direct
1.1

Write s=j=1mcjχEj. Then for every measurable A,[L1, L2, given, algebra] νs(A)=Asdμ=j=1mcjμ(AEj).

2.1

Step 1.1 gives νs()=0. If (An) is a pairwise disjoint[step 1.1, L2, L3, algebra] measurable sequence, then each (AnEj) is pairwise disjoint, so νs ⁣(nAn)=j=1mcjμ ⁣(n(AnEj))=j=1mcjnμ(AnEj)=nνs(An).

3.1

Therefore νs satisfies the two conditions in [L3], so it is a [step 2.1, L3] ∎ measure.

Depends on

Used by

Dependency tree · two levels

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Sources