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The Whitney trick realizes algebraic middle-handle cancellation geometrically

Statement

Assume ACω (The Axiom of Countable Choice (ACω)). Let (W;M0,M1) be a connected simply connected h-cobordism with dim⁡W=n+1≥6, presented relative to M0 with handles e1,…,er of index k and g1,…,gr of index k+1, 2≤k≤n−2, with middle-handle intersection matrix equal to the identity Ir (all intersections transverse, the oriented intersection numbers being δij) (The middle-handle intersection matrix of an h-cobordism). Then there is a presentation of W relative to M0 with the same handles such that, for every i,j, the attaching sphere Ai of gi meets the belt sphere Bj of ej transversely with Ai∩Bj a single point if i=j and Ai∩Bj=∅ if i≠j. The modification is realised by isotopies of the attaching embeddings; equivalently the algebraic identity matrix is upgraded to a geometric single-point configuration.

Facts & Assumptions

Given: A connected simply connected h-cobordism with dim⁡W=n+1≥6, a presentation with handles only in indices k,k+1, 2≤k≤n−2, and middle-handle matrix Ir; ACω.

[F1]

The middle level is a closed simply connected n-manifold V in which the attaching and belt spheres have complementary dimensions k and n−k, and transverse intersections are finite (Transverse complementary-dimensional intersection sets, Compact transverse complementary intersections are finite, Simply connected topological spaces).

[F2]

Two distinct points of a connected embedded closed submanifold of dimension at least two can be joined by a smooth embedded arc whose interior avoids any prescribed finite set (Arcs joining two points of a connected submanifold avoiding finitely many points).

[F3]

The high-dimensional Whitney trick removes a pair of opposite-sign transverse intersection points of two embedded spheres of dimensions a,b≥3 in an ambient manifold of dimension a+b when the Whitney circle is null-homotopic (The high-dimensional Whitney trick).

[F4]

For k=2, the incoming h-cobordism fundamental-group isomorphism gives injection of the complement of the actual belt spheres. For k=n−2, reverse the k,k+1 presentation: the original attaching spheres become belts of the dual 2-handles, so their full complement has the same fundamental group as the level. Both are handle-complement statements, not consequences of simple connectivity alone. Belt-sphere complements in low handle levels preserve the fundamental group, Handle duality from negating a Morse function.

[F5]

Isotoping an attaching embedding through embeddings in its boundary region does not change the presented manifold relative to the incoming boundary (Isotopic attaching embeddings give diffeomorphic handle attachments).

Proof

1.1F1F2given

Work in the common middle level of the entire two-index presentation, before isolating any pair of critical points. That level is simply connected: the reverse trace through the k-handles and the later forward handles have indices at least three, so both its fundamental group and that of W agree. By [F1] the intersections are finite, and each (i,j) signed sum is δij. Any surplus set therefore has an opposite-sign pair. Both sheet dimensions k and n−k are at least two, so choose its two sheet arcs avoiding every other intersection by [F2]; their circle contracts in this level.

2.1F3F4step 1.1

For 3≤k≤n−3, apply [F3], choosing the disk and tube to avoid every other attaching and belt sphere by codimension at least three. For k=2, apply the belt-complement construction of [F4] from M0: fill the shifted loop in the complement of all belts and clear the finitely many 2-sphere attaching images, obtaining an admissibly framed disk with no other incidences. This moves only the selected attaching sphere and keeps the entire attaching family embedded and disjoint.

2.2F2F4step 1.1

For k=n−2, view the level from M1. The original attaching spheres are the belts of its dual 2-handles by [F4]. Exchange the selected sheets and use the helper to isotope the original belt Bj≅S2 against the fixed original attaching sphere Ai, with the disk in the complement of every Al and avoiding every other Bl≅S2. The two signs remain opposite when the sheets are exchanged, and the loop is still null. If the auxiliary ambient isotopy is Ht, apply Ht−1 to Ai alone and leave the original belts fixed. The identity H1−1(Ai)∩Bj=H1−1(Ai∩H1(Bj)) removes exactly the pair. Its tube avoids all other attaching spheres and belts, so their configurations stay fixed. This proves the flipped endpoint for the actual handle spheres.

3.1F1F3F4F5step 2.1step 2.2∎

Repeat the appropriate pair removal finitely. Every step decreases the intersection count by two, preserves the other intersections and transports the attaching framing. The invariant signed sums leave exactly one transverse point when i=j and none when i≠j. By [F5] the resulting isotopies of the attaching embeddings preserve the presented cobordism relative to M0. The same handles therefore realize the geometric identity matrix for every 2≤k≤n−2. No early critical-level rearrangement is required before the geometric disjunction has been achieved.

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