Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The finite uniformized matrix is column stochastic

Statement

Let Q be a finite column generator and let ν≥max⁡j<nrj. If ν>0, then

P:=I+Q/ν

has nonnegative entries and every column sums to one. If ν=0, then Q=0.

Facts & Assumptions

Given: A finite column generator Q=(qij)i,j<n, its exit rates rj, and ν≥max⁡jrj.

[F1]

Finite column generator: qij≥0 for i≠j, rj=−qjj=∑i≠jqij, and ∑iqij=0 for every column j.

Proof

technique · direct
1.1givenF1algebra

Suppose ν>0. For i≠j, Pij=qij/ν≥0 by [F1]. For a diagonal entry, Pjj=1−rj/ν≥0 because rj≤ν. Thus every entry is nonnegative.

2.1F1step 1.1algebra

For each source column j, [F1] gives ∑iPij=∑i(δij+qij/ν)=1+ν−1∑iqij=1. Hence P is column stochastic.

3.1givenF1algebra∎

If ν=0, the bound 0≤rj≤ν gives rj=0 for every j. Each finite sum rj=∑i≠jqij consists of nonnegative terms, so each off-diagonal entry in column j is zero; the column-sum condition then gives qjj=0. Therefore Q=0.

Depends on

Used by

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources