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PropositionStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-12
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Central idempotents under the Brauer homomorphism

Statement

For a central block idempotent b∈kG, Br⁡P(b) is a central idempotent of kCG(P), possibly zero. It equals the sum of exactly those primitive central idempotents e for which Br⁡P(b)e=e.

Facts & Assumptions

Given: A block b and a p-subgroup P.

[F1]

The Brauer map is a unital surjective algebra homomorphism. (Brauer homomorphism is multiplicative)

[F2]

The identity is the sum of orthogonal primitive central block idempotents. (p-blocks from primitive central idempotents)

Proof

technique · direct
1.1F1

Multiplicativity gives Br⁡P(b)2=Br⁡P(b). Every element c of the target has a lift a in the domain. Since b commutes with a, their images commute, so Br⁡P(b) is central.

2.1F2step 1.1∎

Write 1=∑ej for the block decomposition of the centralizer algebra. Each Br⁡P(b)ej is a central idempotent below primitive ej, so is either zero or ej: otherwise it and ej−Br⁡P(b)ej split ej. Multiplying the decomposition of one by Br⁡P(b) yields exactly the asserted sum. If all products vanish, the sum is empty and equals zero.

Sources

Webb, A Course in Finite Group Representation Theory, §§11.3, 11.6 and 12.3–12.5, especially pp.240–245. Local argument and conventions as displayed above.

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources