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PropositionStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-12
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Central idempotents under the Brauer homomorphism

Statement

For a central block idempotent bkG, BrP(b) is a central idempotent of kCG(P), possibly zero. It equals the sum of exactly those primitive central idempotents e for which BrP(b)e=e.

Facts & Assumptions

Given: A block b and a p-subgroup P.

[F1]

The Brauer map is a unital surjective algebra homomorphism. (Brauer homomorphism is multiplicative)

[F2]

The identity is the sum of orthogonal primitive central block idempotents. (p-blocks from primitive central idempotents)

Proof

technique · direct
1.1

Multiplicativity gives BrP(b)2=BrP(b). Every element c of the target has a lift a in the domain. Since b commutes with a, their images commute, so BrP(b) is central.

F1
2.1

Write 1=ej for the block decomposition of the centralizer algebra. Each BrP(b)ej is a central idempotent below primitive ej, so is either zero or ej: otherwise it and ejBrP(b)ej split ej. Multiplying the decomposition of one by BrP(b) yields exactly the asserted sum. If all products vanish, the sum is empty and equals zero.

F2step 1.1

Sources

Webb, A Course in Finite Group Representation Theory, §§11.3, 11.6 and 12.3–12.5, especially pp.240–245. Local argument and conventions as displayed above.

Depends on

Used by

Dependency tree · two levels

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Sources