Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-13
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Degree of the antipodal map on the sphere

Statement

Give Sn=Dn+1 its outward-normal-first boundary orientation. For n1, the antipodal diffeomorphism A:SnSn, A(x)=x, has deg(A)=(1)n+1.

Facts & Assumptions

Given: The oriented sphere and antipodal map in the statement.

[F1]

Induced boundary orientation says that (v1,,vn) is positive in TxSn exactly when (x,v1,,vn) is positive in the ambient Rn+1.

[F2]

Pointwise orientation sign of a local diffeomorphism identifies the orientation behavior of a local diffeomorphism from the determinant sign of its differential.

[F3]

Degree of an orientation-preserving or reversing diffeomorphism gives degree 1 for an orientation-preserving diffeomorphism and 1 for an orientation-reversing one.

Proof

technique · direct orientation comparison
1.1

The map A is smooth and satisfies A1=A, hence is a diffeomorphism. Fix xSn and a positive tangent basis (v1,,vn) at x. Its image basis at x is (v1,,vn). By [F1], its boundary-orientation sign is the ambient sign of (x,v1,,vn)=(1)n+1(x,v1,,vn). Thus [F2] makes A orientation preserving when n+1 is even and orientation reversing when n+1 is odd.

F1F2given
2.1

Applying [F3] in the two parity cases gives deg(A)=(1)n+1. For n=1 this is +1, agreeing with the half-turn of the oriented circle; for even n it is 1. The excluded n=0 case has a disconnected sphere and lies outside the degree definition used here. There are no endpoint, fibre, or choice issues: the calculation is pointwise and the same sign holds at every x.

F3step 1.1

Depends on

Used by

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Dependency tree · two levels

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Sources