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Formal equivalence changes the first-order cochain by a Hochschild coboundary

Statement

Let ⋆ and ⋆′ be formally gauge equivalent differential star products on a real Poisson manifold, with first coefficients B1 and B1′. If their gauge map is T=id⁡+ℏD1+O(ℏ2), then B1′(f,g)=B1(f,g)+(δD1)(f,g),(δD1)(f,g)=fD1(g)−D1(fg)+D1(f)g. Consequently B1 and B1′ define the same class in HHdiff,norm2(C∞(M),C∞(M)), and their skew parts are identical. This is a first-order invariant only; it does not classify full star products.

Facts & Assumptions

Given: A commutative real algebra A=C∞(M,R), two differential star products on A⟦ℏ⟧, and a gauge map T as in [F1].

[F1]

Formal differential star products and first-order normalization: the products are associative, their coefficients are bidifferential, and they preserve the unit.

[F2]

Formal differential gauge equivalence of star products: T=id⁡+∑r≥1ℏrDr, with differential coefficients vanishing on 1, and f⋆′g=T−1(Tf⋆Tg).

[F3]

Hochschild cochains, differential, and Gerstenhaber insertion bracket: for a 1-cochain D, (δD)(f,g)=fD(g)−D(fg)+D(f)g.

[F4]

The shifted Hochschild cochains form a differential graded Lie algebra: δ2=0, so the normalized multidifferential cocycles modulo coboundaries define the stated Hochschild cohomology group.

Proof

1.1givenF1F3F4algebra

The coefficient of ℏ in associativity of ⋆ is B1(f,g)h+B1(fg,h)−fB1(g,h)−B1(f,gh)=0, which is −(δB1)(f,g,h)=0. The same calculation applies to ⋆′, so both first coefficients are normalized 2-cocycles in the complex of [F4].

1.2F2givenalgebra

Comparing coefficients of ℏ in TT−1=id⁡ gives T−1=id⁡−ℏD1+O(ℏ2).

2.1F2F3step 1.2algebra

Expand the defining transformation from [F2] through first order: Tf⋆Tg=fg+ℏ(D1(f)g+fD1(g)+B1(f,g))+O(ℏ2). Applying T−1 subtracts ℏD1(fg), hence B1′=B1+fD1(g)−D1(fg)+D1(f)g=B1+δD1 by [F3].

3.1givenF3F4step 1.1step 2.1algebra∎

Since A is commutative, δD1(f,g)=fD1(g)−D1(fg)+D1(f)g equals δD1(g,f). Thus the skew parts of B1 and B1′ agree, and their difference is the coboundary δD1. With step 1.1 this proves equality of their classes in the cohomology of [F4].

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