Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-27
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Free abelian groups of rank at least two are not hyperbolic

Statement

If A is a free abelian group of rank at least 2, then A is not hyperbolic.

Facts & Assumptions

Given: A free abelian group A of rank n2.

[L1]

Hyperbolicity of a finitely generated group is independent of the chosen finite generating set (Hyperbolicity of a finitely generated group is independent of the finite generating set).

[L2]

Hyperbolic spaces have uniformly thin geodesic quadrilaterals (Hyperbolic spaces have thin geodesic quadrilaterals).

[A1]

With the standard basis of Zn, the Cayley graph contains geodesic rectangles of arbitrarily large width inside the first two coordinate directions.

Proof

technique · direct
1.1

By the rank hypothesis, AZn with n2. In the standard Cayley graph, the points (0,0), (m,0), (m,m), and (0,m) in the first two coordinates form a geodesic square of side length m for every m1.

givenA1algebra
2.1

If the standard Cayley graph were hyperbolic, [L2] would give a uniform thinness constant for all geodesic quadrilaterals. But the midpoint of one side of the square from step 1.1 has distance m/2 from the union of the opposite sides, and m is arbitrary. So the standard Cayley graph is not hyperbolic, and [L1] shows that A itself is not hyperbolic.

A1L1L2step 1.1

Depends on

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