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The profile moments of Ω are central binomial coefficients

Statement

For the limit profile Ω of The Logan-Shepp-Vershik-Kerov limit profile Ω, p~2m[Ω]=(2m)!m! m!=(2mm)(m≥1),p~k[Ω]=0(k odd), and p~1[Ω]=0 by the declaration of Shifted character observables pρ# and profile moments p~k.

Facts & Assumptions

Given: the even profile Ω and its profile moments p~k[ω]=k(k−1)∫Rxk−2σω(x) dx, σω=12(ω−∣x∣) (The Logan-Shepp-Vershik-Kerov limit profile Ω, Shifted character observables pρ# and profile moments p~k).

[F1]

Ω is even, Ω(x)=∣x∣ for ∣x∣≥2, and for ∣x∣<2 it is C1 with Ω′(x)=2πarcsin⁡x2 (The Logan-Shepp-Vershik-Kerov limit profile Ω). Hence σΩ=12(Ω−∣x∣) is even, vanishes outside [−2,2], and is continuous and piecewise C1 on [−2,0] and [0,2], with σΩ(±2)=0; integrating by parts on the two pieces gives, for k≥2, ∫Rxk−1σΩ′(x) dx=−(k−1)∫Rxk−2σΩ(x) dx (all boundary terms vanish: at ±2 because σΩ vanishes there, at 0 because k−1≥1), so −k∫Rxk−1σΩ′=k(k−1)∫Rxk−2σΩ=p~k[Ω] (Shifted character observables pρ# and profile moments p~k).

[F2]

Monotone change of variables: if φ:[c,d]→[a,b] is a monotone differentiable bijection with integrable derivative and f is Riemann integrable on [a,b], then ∫abf=∫cd(f∘φ) ∣φ′∣ (Monotone change of variable for Riemann-integrable functions).

[F3]

Wallis integrals: I2m=∫0π/2sin⁡2mθ dθ=π2∏k=1m2k−12k=π2⋅(2m−1)!!(2m)!! for m≥0 (Wallis integrals satisfy the two-step recurrence, closed forms, and the adjacent-integral squeeze); and (2m)!=2mm! (2m−1)!! (The factorial n! and the falling factorial nk‾, defined by recursion in N).

[F4]

Arcsine: arcsin⁡(sin⁡θ)=θ for θ∈[0,π/2] (Principal inverse sine and inverse cosine), and sin⁡ and cos⁡ have the usual derivatives (The derivatives of sine and cosine are cosine and minus sine).

[F5]

Integration by parts on a closed interval: if u,v are differentiable on [a,b] with integrable derivatives then ∫abuv′=u(b)v(b)−u(a)v(a)−∫abu′v (If u,v are differentiable on [a,b] with u′,v′ integrable, then ∫abuv′=u(b)v(b)−u(a)v(a)−∫abu′v).

Proof

technique · direct
1.1givenF1algebra

Odd moments vanish: σΩ is even and supported in [−2,2] by [F1], so for odd k≥3 the integrand xk−2σΩ(x) is odd and its integral over the symmetric interval vanishes; hence p~k[Ω]=0 for odd k by the definition, and p~1[Ω]=0 by the convention.

1.2givenF1algebra

Reduction for even moments: fix m≥1 and put k=2m. By [F1] and the integration-by-parts form of the profile moment, p~2m[Ω]=−2m∫Rx2m−1σΩ′(x) dx=−m∫−22x2m−1(2πarcsin⁡x2−sgn⁡x)dx. The integrand is even (odd factor times the odd function 2πarcsin⁡(x/2)−sgn⁡x), so the integral equals 2m∫02x2m−1(1−2πarcsin⁡x2)dx=∫02(1−2πarcsin⁡x2)d(x2m).

2.1givenF2F4step 1.2algebra

Substitution x=2sin⁡θ: by [F2] applied to the increasing bijection θ↦2sin⁡θ from [0,π/2] onto [0,2] (with 2cos⁡θ≥0 and arcsin⁡(sin⁡θ)=θ by [F4]), the integral of step 1.2 equals ∫0π/2(1−2πθ)⋅4m 22m−1sin⁡2m−1θcos⁡θ dθ.

3.1givenF3step 2.1algebra

Integration by parts and Wallis: on [0,π/2] put u(θ):=1−2πθ and v(θ):=sin⁡2mθ2m; both are differentiable with continuous derivatives u′≡−2π and v′=sin⁡2m−1θcos⁡θ, so [F5] gives ∫0π/2uv′=[uv]0π/2−∫0π/2u′v=2π⋅12m∫0π/2sin⁡2mθ dθ=I2mπm, because u(π/2)=0 and u(0)=1 while v(0)=sin⁡0=0. Multiplying by 4m 22m−1 and using [F3], p~2m[Ω]=22m+1πI2m=22m+1π⋅π2⋅(2m−1)!!(2m)!!=22m(2m−1)!!2mm!=(2m)!m! m!, where the last equality is (2m)!=2mm!(2m−1)!! of [F3].

4.1givenstep 1.1step 3.1∎

Conclusion: step 1.1 gives the vanishing for odd k (including p~1=0 by convention) and steps 1.2, 2.1, 3.1 give p~2m[Ω]=(2mm) for every m≥1.

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