Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passverified 2026-08-10 (gpt-5.6-terra-codex-subscription)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

If u,v are differentiable on [a,b] with u′,v′ integrable, then ∫abuv′=u(b)v(b)−u(a)v(a)−∫abu′v

Statement

Let a<b be reals and let u,v:[a,b]→R be differentiable at every point of [a,b] as functions on [a,b] (The derivative f′(c)=lim⁡x→cf(x)−f(c)x−c of f:A→R at a point c∈A that is a limit point of A, and differentiability on a set). Suppose u′ and v′ are integrable on [a,b] (The lower and upper Darboux integrals of a bounded f on [a,b] as sup⁡PL(f,P) and inf⁡PU(f,P), Darboux integrability as their equality, and the notation ∫abf). Then uv′ and u′v are integrable and

∫abu v′  =  u(b)v(b)−u(a)v(a)  −  ∫abu′ v.

The integrability of u′ and v′ is a hypothesis, not a formality. Without it the two integrals in the display need not exist at all, and the identity is then not false but ill-formed; that is the false statement that deletes it on the companion page. The hypothesis is automatic when u and v are continuously differentiable, since a continuous function on [a,b] is integrable (A continuous function on [a,b] is Riemann integrable, by Heine-Cantor and Riemann's criterion).

Facts & Assumptions

Given: Reals a<b and functions u,v:[a,b]→R, differentiable at every point of [a,b], with u′ and v′ integrable on [a,b].

[L5]

Sums of integrable functions are integrable, and ∫ab(w1+w2)=∫abw1+∫abw2 (Integrable functions on [a,b] form a set closed under sums and scalar multiples, and ∫ab(λf+μg)=λ∫abf+μ∫abg).

[L6]

If H is differentiable at every point of [a,b] with H′ integrable there, then ∫abH′=H(b)−H(a) (The second fundamental theorem: if G is differentiable on [a,b] with G′=f and f is integrable, then ∫abf=G(b)−G(a)).

Proof

technique · direct
1.1

u and v are continuous on [a,b] by [L2], hence integrable there by [L3].

givenL2L3
1.2

uv is differentiable at every point of [a,b] with (uv)′=u′v+uv′ by [L1].

givenL1
2.1

u′v and uv′ are integrable on [a,b] by [L4], being products of the integrable u′ with v and of u with the integrable v′.

step 1.1givenL4
3.1

Hence (uv)′=u′v+uv′ is integrable by [L5], and ∫ab(uv)′=∫abu′v+∫abuv′.

step 1.2step 2.1L5
4.1

By [L6] applied to H:=uv, ∫ab(uv)′=u(b)v(b)−u(a)v(a).

step 1.2step 3.1L6
5.1

Comparing steps 3.1 and 4.1 and subtracting ∫abu′v gives ∫abuv′=u(b)v(b)−u(a)v(a)−∫abu′v.

step 3.1step 4.1algebra∎

Remarks

Depends on

Used by

Dependency tree · two levels

55 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources