Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-08-30
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The Gamma functional equation

Statement

For every z with Re⁡z>0,

Γ(z+1)=zΓ(z).

Facts & Assumptions

Given: A complex number z with Re⁡z>0.

[L2]

The Gamma integral converges locally uniformly on right-half-plane compact sets (Euler's Gamma integral converges locally uniformly on the right half-plane).

[L3]

Euler's Gamma function is the improper integral ∫0∞tz−1e−t dt on Re⁡z>0 (Euler's Gamma function on the right half-plane).

Proof

technique · direct
1.1givenL1

For 0<ε<R, apply [L1] on [ε,R] with u(t)=tz and v′(t)=e−t. This gives ∫εRtze−t dt=[−tze−t]εR+z∫εRtz−1e−t dt.

2.1step 1.1L2L3algebra∎

Since Re⁡z>0, one has ∣εze−ε∣=εRe⁡ze−ε→0 as ε↓0, and ∣Rze−R∣=RRe⁡ze−R→0 as R↑∞. Passing to the improper limits in step 1.1 and using [L2] and [L3] gives Γ(z+1)=zΓ(z).

Depends on

Used by

Dependency tree · two levels

15 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources