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PropositionStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-22
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Moment map components generate the negative infinitesimal action

Statement

Assume ACω. Let μ:Mg be an infinitesimal moment map for a symplectic action, so that dμξ=ιξMω for every ξg. Then for every ξ the Hamiltonian vector field of the component μξ is the negative of the fundamental field:

Xμξ=ξM.

Facts & Assumptions

Given: ACω, a symplectic action, an infinitesimal moment map μ, and ξg.

[A1]

ACω is countable choice; it is used only through the fundamental-field dependency of [F1].

[F1]

The component moment equation reads dμξ=ιξMω. Moment map, component Hamiltonians and infinitesimal moment maps.

[F2]

ι is linear in its vector-field slot, so ιξMω=ιξMω. Hamiltonian vector field and Hamiltonian function.

[F3]

For every smooth H there is a unique smooth vector field XH satisfying ιXHω=dH. Hamiltonian vector fields exist uniquely for smooth functions.

Proof

technique · direct
1.1

By [F1] and [F2], dμξ=ιξMω=ιξMω: the covector dμξ is obtained by contracting ω with the field ξM.

F1F2given
2.1

The field ξM is smooth because ξM is. So ξM is a smooth vector field whose contraction with ω equals dμξ, the differential of the smooth function μξ.

step 1.1
3.1

By [F3] the field Xμξ with ιXμξω=dμξ exists and is the only such field, and [step 1.1] exhibits ξM as such a field; hence Xμξ=ξM.

A1F3step 2.1

Depends on

Used by

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources