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Moment map components generate the negative infinitesimal action
Statement
Assume . Let be an infinitesimal moment map for a symplectic action, so that for every . Then for every the Hamiltonian vector field of the component is the negative of the fundamental field:
Facts & Assumptions
Given: , a symplectic action, an infinitesimal moment map , and .
is countable choice; it is used only through the fundamental-field dependency of [F1].
The component moment equation reads . Moment map, component Hamiltonians and infinitesimal moment maps.
is linear in its vector-field slot, so . Hamiltonian vector field and Hamiltonian function.
For every smooth there is a unique smooth vector field satisfying . Hamiltonian vector fields exist uniquely for smooth functions.
Proof
By [F1] and [F2], : the covector is obtained by contracting with the field .
The field is smooth because is. So is a smooth vector field whose contraction with equals , the differential of the smooth function .
By [F3] the field with exists and is the only such field, and [step 1.1] exhibits as such a field; hence .
Depends on
Used by
- The characteristic kernel on a regular moment level Lemma
- The differential of the moment map and the orbit-orthogonal identity Lemma
- The nonequivariance defect of an infinitesimal moment map is a constant Lie-algebra two-cocycle Lemma
- For connected groups, equivariance is equivalent to the moment-map Poisson bracket identity Proposition
- Noether's conservation law for Hamiltonian actions Theorem
Dependency tree · two levels
13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Ana Cannas da Silva, Lectures on Symplectic Geometry (standard reference, not scraped)
- Eckhard Meinrenken, Symplectic Geometry (standard reference, not scraped)