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Open subspaces and residual subspaces of Baire spaces are Baire
Statement
Every open subspace of a Baire space is Baire. Every residual subspace of a Baire space, with its subspace topology, is Baire.
Facts & Assumptions
Given: The objects, hypotheses, and choice principles stated above.
For a topological space , the following are equivalent: every countable intersection of dense open sets is dense; every countable union of closed sets with empty interior has empty interior; no nonempty open subset is meagre in ; and every residual subset meets every nonempty open set. The equivalence includes the empty space. (Equivalent forms of the Baire property).
A set is residual when its complement is contained in the union of one sequence of nowhere dense sets (Nowhere dense, meagre, residual, and comeagre subsets of a topological space).
Let be a topological space (def-topological-space) and let . The subspace topology (also relative topology) on is the family of traces on of the open sets of . The pair is a subspace of . A subset of that lies in is said to be open in , and relatively open where the ambient space needs emphasis. (Subspace topology: the traces of the open sets, its closed sets and its bases, the continuity of the inclusion, and the characteristic property of a map into a subspace).
Proof
Let be open in a Baire space , and let be dense open subsets of . Put and . Each is nowhere dense in : if a nonempty -open lay in , then would meet (since ), while the nonempty relatively open would lie in , contradicting density of in .
Let be residual in . By [F2], fix one sequence of nowhere dense subsets with . Since no nonempty open subset of a Baire space is meagre [F1], is dense in .
The sets are dense open in . By the Baire property, their intersection meets every nonempty open subset of ; a point in that intersection and lies in every . Thus is Baire, including the empty case.
Let be dense open subsets of . Put and . Because is dense, each is nowhere dense in : otherwise a nonempty -open would meet , and the nonempty relatively open would lie in , contradicting density of in .
The single interleaved sequence witnesses that is meagre; forming it requires no countable selection of witnesses. Given a nonempty relatively open in , is nonempty open in . By [F1], is not contained in that meagre set. Any point of outside it belongs to and every , hence to . Therefore is Baire.
Steps 2.1 and 3.1 establish both assertions.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- David Marker, Descriptive Set Theory, §§1–2 (standard reference, not scraped)
- Michael Kunzinger, General Topology, §§11.3–11.4 (standard reference, not scraped)
- MFF General Topology course summary, §4.3 (standard reference, not scraped)
- Jesse Peterson, Real Analysis, §§3.6–3.7 (standard reference, not scraped)