Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Pullback connections intertwine parallel transport

Statement

For f:NM smooth and γ:[a,b]N piecewise smooth, let Jt:(fE)γ(t)Ef(γ(t)) be the canonical fibre identification. Then JbPγf=PfγJa.

Facts & Assumptions

Given: A connection on E, the map f and the curve γ.

[F1]

Pullback connections are functorial under the canonical bundle identifications (Pullback connection is well defined and functorial).

[F2]

Parallel sections with an initial value are unique (Existence and uniqueness of parallel sections).

[F3]

Transport is endpoint evaluation of that section (Parallel transport along a piecewise smooth curve).

Proof

1.1

The fibre identifications give the canonical isomorphism γ(fE)(fγ)E. Functoriality identifies their connections and hence their derivatives in direction t. Thus they identify parallel sections, piecewise and continuously at all corners. Explicitly, both coefficient equations use ωf(γ(t))(dfγ(t)γ˙(t)).

F1
2.1

A parallel section on the left with initial vector v corresponds to one on the right with initial vector Jav. Uniqueness and endpoint evaluation give the asserted identity on every v. Constant f gives zero matrix in a fixed target fibre frame; no injectivity of f or nonzero curve velocity is required. For a=b the two sides are Ja, and rank-zero bundles have the unique maps. The identifications are canonical, not selected trivializations.

F2F3step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources