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Restriction and induction along a subgroup preserve projective modules
Statement
Let be finite groups and let be a field. Then restriction and induction both send projective modules to projective modules.
Facts & Assumptions
Given: A subgroup and a field .
Projective modules are characterized by lifting and by being direct summands of free modules (Projective modules and the lifting property, Equivalent characterizations of projective modules).
Induction is left adjoint to restriction (Induction is left adjoint to restriction for finite-group modules over a commutative ring).
A left transversal identifies with a finite direct sum of copies of (A left transversal identifies with a direct sum of copies of ).
Proof
Let be a projective -module. By [F1], it is a direct summand of a free module . Restricting to preserves direct sums and summands. By [L2] with , the restricted regular module is a finite direct sum of copies of , hence is free as a -module. Therefore is a direct summand of a free -module and is projective by [F1].
Let be a projective -module. To prove that is projective, use the lifting characterization in [F1]. Given a surjection of -modules and a map , adjunction [L1] turns into a map . The restriction of is still surjective, so projectivity of lifts to . Applying [L1] again yields a lift of . Thus is projective.
Steps 1.1 and 2.1 prove that both restriction and induction preserve projectives.
Depends on
Used by
Dependency tree · two levels
16 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Peter Webb, A Course in Finite Group Representation Theory (23 Feb 2016 draft) (standard reference, not scraped)