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PropositionStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-04
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Restriction and induction along a subgroup preserve projective modules

Statement

Let H≤G be finite groups and let k be a field. Then restriction Res⁡HG and induction Ind⁡HG both send projective modules to projective modules.

Facts & Assumptions

Given: A subgroup H≤G and a field k.

[F1]

Projective modules are characterized by lifting and by being direct summands of free modules (Projective modules and the lifting property, Equivalent characterizations of projective modules).

[L2]

A left transversal identifies Ind⁡HGW with a finite direct sum of copies of W (A left transversal identifies Ind⁡HGW with a direct sum of [G:H] copies of W).

Proof

technique · direct
1.1F1L2givenalgebra

Let P be a projective kG-module. By [F1], it is a direct summand of a free module (kG)n. Restricting to H preserves direct sums and summands. By [L2] with W=kH, the restricted regular module Res⁡HG(kG) is a finite direct sum of copies of kH, hence is free as a kH-module. Therefore Res⁡HGP is a direct summand of a free kH-module and is projective by [F1].

2.1F1L1step 1.1algebra

Let Q be a projective kH-module. To prove that Ind⁡HGQ is projective, use the lifting characterization in [F1]. Given a surjection u:X→Y of kG-modules and a map ϕ:Ind⁡HGQ→Y, adjunction [L1] turns ϕ into a map ψ:Q→Res⁡HGY. The restriction of u is still surjective, so projectivity of Q lifts ψ to ψ~:Q→Res⁡HGX. Applying [L1] again yields a lift ϕ~:Ind⁡HGQ→X of ϕ. Thus Ind⁡HGQ is projective.

3.1step 1.1step 2.1∎

Steps 1.1 and 2.1 prove that both restriction and induction preserve projectives.

Depends on

Used by

Dependency tree · two levels

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Sources