Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-31
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Smoothness of a map on an embedded submanifold is local in the ambient space

Statement

Let S⊆M be an embedded submanifold and let f:S→N be a map to a smooth manifold N. Then f is smooth if and only if every point p∈S has an open neighbourhood U⊆M and a smooth map f~:U→N such that f~∣U∩S=f∣U∩S.

Facts & Assumptions

Given: An embedded submanifold S⊆M and a map f:S→N.

[F1]

Embedded submanifolds have slice charts (Embedded submanifolds and slice charts).

[L1]

A map into an embedded submanifold is smooth exactly when its ambient composite is smooth (Smoothness into an embedded submanifold is an initial property).

[L2]

Smooth maps are continuous (Smooth maps are continuous).

Proof

technique · direct
1.1F1L2givenconstruct

Assume f is smooth. Fix p∈S and choose a slice chart φ:U→Ω⊆Rm with φ(S∩U)=Ω∩(Rk×{0}). In these coordinates, the representative of f∣S∩U depends only on the first k variables. Extend it to all of Ω by ignoring the last m−k coordinates. Transporting this extension back gives a smooth f~:U→N with f~∣U∩S=f∣U∩S.

2.1L1step 1.1given

Conversely, suppose every point has such an ambient extension. On each U∩S, the restriction of f~ to the embedded submanifold U∩S is smooth by [L1], so f is smooth near every point of S. Smooth maps being local on the source, f is smooth on all of S.

3.1step 1.1step 2.1∎

Therefore the ambient-extension criterion is equivalent to smoothness of f.

Depends on

Used by

Dependency tree · two levels

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Sources