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The double point locus has the expected dimension 2m−n

Statement

Assume ACω. Let f:Mm→Xn be a self-transverse immersion, with double point locus Δ2(f), double point set Σ(f) and swap involution τ(x,y)=(y,x) as in Self-transverse immersions and the double point locus. Then:

  1. Δ2(f) is a closed embedded submanifold of the open submanifold M×M∖ΔM of M×M, and if 2m−n≥0 it has pure dimension 2m−n;
  2. if 2m−n<0, then Δ2(f)=∅ and Σ(f)=∅;
  3. the swap involution restricts to a smooth free involution of Δ2(f); the map q:Δ2(f)⟶X,q(x,y):=f(x)=f(y), is a smooth immersion with image Σ(f) and satisfies q∘τ=q, and every point of Δ2(f) has a neighbourhood on which q is an embedding; q induces a surjection from the orbit set Δ2(f)/τ onto Σ(f) sending an orbit to its common image, and this surjection is a bijection exactly when no point of X is the image of more than two points of M; in that case Σ(f) is the quotient of Δ2(f) by the free involution and q is two-to-one onto its image.

No finiteness of Δ2(f) is asserted.

Facts & Assumptions

Given: Countable choice, a self-transverse immersion f:Mm→Xn, and the notation of Self-transverse immersions and the double point locus.

[F1]

Δ2(f)={(x,y)∈M×M∖ΔM:f(x)=f(y)} and Σ(f)=f(pr⁡1Δ2(f)); self-transversality means that f×f is transverse to ΔX on M×M∖ΔM, i.e. dfx(TxM)+dfy(TyM)=TrX at every double point r=f(x)=f(y) (Self-transverse immersions and the double point locus).

[L1]

If F:P→N is smooth and transverse to an embedded submanifold Z⊆N of codimension c, then F−1(Z) is an embedded submanifold of P of codimension c, and TpF−1(Z)={v∈TpP:dFp(v)∈TF(p)Z} (The transverse preimage theorem).

[L2]

Transversality of a smooth map F to an embedded submanifold Z is the condition dFp(TpP)+TF(p)Z=TF(p)N for all p∈F−1(Z) (A smooth map transverse to an embedded submanifold); for the inclusion ι:Z↪N this is exactly the transversality of the maps F and ι in the sense of Transverse smooth maps.

[L3]

ΔX is a closed embedded submanifold of X×X of dimension n=dim⁡X, and ΔM is a closed embedded submanifold of M×M of dimension m (The diagonal of a smooth manifold is a closed embedded submanifold).

[L4]

If smooth maps F:Ux→Ww and G:Zz→Ww are transverse and x+z<w, then the fibre product U×WZ is empty; in particular transverse embedded submanifolds of dimensions a,b in a manifold of dimension w>a+b do not meet (Negative expected dimension forces empty generic intersections).

[L5]

An embedded k-submanifold has k∈N with 0≤k≤dim⁡M and carries the subspace topology (Embedded submanifolds and slice charts).

[L6]

The differential satisfies d(G∘F)p=dGF(p)∘dFp (The chain rule for differentials of smooth maps), and dFp is a linear map TpP→TF(p)N (The differential of a smooth map).

[L7]

A map out of an embedded submanifold is smooth if and only if it agrees locally with the restriction of a smooth ambient map (Smoothness of a map on an embedded submanifold is local in the ambient space).

[L8]

Every immersion is locally an embedding: at each point some neighbourhood is carried homeomorphically onto an embedded submanifold (Every immersion is locally an embedding).

[L9]

Smooth maps are continuous (Smooth maps are continuous).

[A1]

Countable choice is the hypothesis carried by the transversality machinery used here; the arguments of this proof select nothing further (The Axiom of Countable Choice (ACω)).

Proof

technique · direct
1.1L1L3L5F1A1

The map f×f is smooth on the open submanifold M×M∖ΔM and transverse to ΔX there by [F1]; by [L3] the diagonal ΔX is an embedded submanifold of X×X of codimension 2n−n=n. Applying [L1] to the restriction of f×f to M×M∖ΔM yields that Δ2(f) is an embedded submanifold of M×M∖ΔM of codimension n, that is, of pure dimension 2m−n when 2m−n≥0, and in particular Δ2(f) carries the subspace topology by [L5].

1.2L1L6F1

The tangent space description at a point (x,y)∈Δ2(f) with r=f(x)=f(y): by [L1], a tangent vector lies in T(x,y)Δ2(f) exactly when its image under d(f×f)(x,y) lies in T(r,r)ΔX. By [L6] applied to the components π1∘(f×f)=f∘π1 and π2∘(f×f)=f∘π2, this image is (dfx(v),dfy(w)) for a tangent vector (v,w)∈TxM⊕TyM, while T(r,r)ΔX={(u,u):u∈TrX}; hence T(x,y)Δ2(f)={(v,w)∈TxM⊕TyM:dfx(v)=dfy(w)}.

1.3L3L9F1

The set Δ2(f) is closed in M×M∖ΔM: it is the preimage under the continuous map f×f of the closed set ΔX by [L3] and [L9].

2.1L2L4F1step 1.1

Suppose 2m−n<0, that is 2m+n<2n. The map f×f, restricted to M×M∖ΔM, and the inclusion ΔX↪X×X are transverse by [F1] and [L2], with source dimensions 2m and n and target dimension 2n; by [L4] their fibre product is empty. The fibre product projects bijectively onto the set of pairs (u,δ) with f×f(u)=δ and δ∈ΔX, which is exactly Δ2(f), so Δ2(f)=∅ and hence Σ(f)=f(pr⁡1Δ2(f))=∅.

2.2L7F1step 1.1

The swap τ(x,y)=(y,x) is a diffeomorphism of M×M (an involution, smooth with smooth inverse), and it preserves M×M∖ΔM and the condition f(x)=f(y); hence it restricts to a smooth involution of the embedded submanifold Δ2(f) that is free, since τ(x,y)=(x,y) would force x=y, which is excluded on M×M∖ΔM.

2.3L6L7L8F1step 1.2

The map q(x,y)=f(x)=f(y) is smooth on Δ2(f): it is the restriction of the smooth ambient map M×M∖ΔM→X, (x,y)↦f(x), so the criterion of [L7] applies. Its differential is injective at every point: by [L6], dq(x,y)(v,w)=dfx(v) for (v,w)∈T(x,y)Δ2(f); if dq(x,y)(v,w)=0 then dfy(w)=dfx(v)=0 by the description of step 1.2, so w=0 and then v=0 because dfx and dfy are injective. Hence q is an immersion, and by [L8] every point of Δ2(f) has a neighbourhood on which q is an embedding onto an embedded submanifold of X.

3.1F1step 2.3

By definition of Σ(f) as f(pr⁡1Δ2(f)) the image of q is Σ(f), and q∘τ=q because τ only exchanges the two coordinates, which have equal images.

4.1F1step 3.1

The fibres of q are unions of τ-orbits: q(x,y)=r if and only if x and y are two distinct points of the preimage f−1(r), so q−1(r) is in bijection with the ordered pairs of distinct points of f−1(r), on which τ acts by exchanging the two entries. Consequently q induces a well-defined surjection Δ2(f)/τ→Σ(f) sending the orbit of (x,y) to f(x), and this map is injective exactly when every fibre f−1(r) with r∈Σ(f) consists of exactly two points, that is, exactly when no point of X is the image of more than two points of M.

5.1step 1.1step 1.3step 2.1step 2.2step 2.3step 3.1step 4.1∎

The claims are steps 1.1 and 1.3 for clause 1, step 2.1 for clause 2, and steps 2.2, 2.3, 3.1 and 4.1 for clause 3. No finiteness of Δ2(f) was used or asserted.

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