How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
The transverse preimage theorem
Statement
Let be smooth and let be an embedded submanifold of codimension . If , then is an embedded submanifold of of codimension . For each ,
Facts & Assumptions
Given: A smooth map transverse to an embedded submanifold .
Embedded submanifolds admit local defining submersions (Embedded submanifolds admit local defining submersions).
Transversality to is equivalent to surjectivity on the normal quotient (Transversality is equivalent to surjectivity on the normal quotient).
A regular level set is an embedded submanifold, and its tangent space is the kernel of the defining submersion differential (A regular level set is an embedded submanifold, The tangent space of a regular level set is the kernel).
Proof
Fix and put . By [L1], choose a neighbourhood of and a submersion such that .
At , the differential kills exactly . Therefore [L2] implies that is surjective. So is a regular value of near .
Since , [L3] shows that this set is an embedded codimension- submanifold near , with tangent space
Because was arbitrary, these local models glue to an embedded submanifold structure on with the stated tangent-space formula.
Depends on
Used by
- Transverse embedded submanifolds intersect in the expected codimension Corollary
- The intersection of coordinate spheres as a transverse level set Example
- A preimage need not be a submanifold without transversality False statement
- Parametric transversality Theorem
- Transverse fibre products are embedded submanifolds Theorem
Dependency tree · two levels
13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- John M. Lee, Introduction to Smooth Manifolds, 2nd ed. (standard reference, not scraped)
- Marco Gualtieri, Topology I: Smooth Manifolds, cumulative notes (standard reference, not scraped)