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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
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A regular level set is an embedded submanifold

Statement

Let F:Mm→Nn be smooth, let q∈N be a regular value, and assume F−1(q) is nonempty. Then F−1(q) is an embedded submanifold of codimension n. Equivalently, it has dimension m−n.

Facts & Assumptions

Given: A smooth map F:Mm→Nn and a regular value q∈N with nonempty fibre.

[F1]

A regular value is one whose fibre points are all submersion points; the fibre may be empty (Regular and critical points and values).

[F2]

Codimension means ambient dimension minus submanifold dimension, and embedded submanifolds are defined by slice charts (Codimension and hypersurfaces, Embedded submanifolds and slice charts).

[L1]

Near any submersion point, suitable coordinates put F into the form (u,v)↦u (Local normal form for submersions).

Proof

technique · direct
1.1F1given

Let p∈F−1(q) be arbitrary. By [F1], F is a submersion at p.

2.1step 1.1L1algebra

Apply [L1] at p. In suitable charts around p and q, the map becomes (u,v)↦u on Rn×Rm−n. After centering q, the fibre is {0}×Rm−n. Permuting the two source-coordinate blocks sends it to the standard slice Rm−n×{0}. Thus F−1(q) is locally an embedded submanifold.

3.1F2step 2.1∎

Since every point of the fibre has such a slice neighbourhood, F−1(q) is an embedded submanifold. Its local model has dimension m−n, so by [F2] the codimension is n.

Depends on

Used by

…and 4 more results.

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources