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Zero-level symplectic reduction and the dimension formula

Statement

Assume ACω. Let (M,ω,G,μ) be a Hamiltonian G-space and suppose that 0g is a regular value of μ, that μ1(0) is nonempty, and that G acts freely and properly on μ1(0). Then the symplectic quotient

M0:=μ1(0)/G

is a symplectic manifold and

dimM0=dimM2dimG.

Facts & Assumptions

Given: ACω, a Hamiltonian G-space, 0 a regular value of μ, a nonempty level μ1(0), and G acting freely and properly on that level.

[A1]

ACω is countable choice; it is used only through the reduction and fundamental-field suppliers.

[F1]

The coadjoint stabilizer of 0 is all of G, because the coadjoint action is linear: g0=0 for every g. The coadjoint representation, action and orbits.

[F2]

Under these hypotheses the reduction theorem applies with α=0 and Gα=G, producing the unique symplectic form ω0 on M0 with πω0=ιω. Marsden--Weinstein--Meyer symplectic reduction.

[F3]

Regularity of 0 means dμp is surjective for every pμ1(0); hence dimkerdμp=dimMdimg and Tpμ1(0)=kerdμp. A regular level set is an embedded submanifold, The tangent space of a regular level set is the kernel, Regular and critical points and values.

[F4]

A smooth free proper action of G on a nonempty manifold of dimension n has a smooth quotient of dimension ndimG, with quotient projection a surjective submersion. Free proper action quotient manifold.

Proof

technique · direct
1.1

By [F1] and [F2] the reduction theorem applies at the level 0 with stabilizer G, so M0=μ1(0)/G is a smooth manifold carrying the unique form ω0 with πω0=ιω, which is symplectic.

F1F2given
2.1

The nonempty level hypothesis allows the regular-level theorem in [F3] to be applied to the smooth map μ:Mg at zero. Since dimg=dimg=dimG, the level has dimension dimMdimg near every point, and its tangent space is kerdμp. Its quotient is nonempty because the level is nonempty, and by [F4] quotienting by the free proper G-action lowers the dimension by dimG. Hence dimM0=dimMdimgdimG=dimM2dimG.

step 1.1F3F4A1

Depends on

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