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PropositionStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedaudited 2026-09-22
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The dimension of a regular reduced space at a nonzero value

Statement

Assume ACω. Let (M,ω,G,μ) be a Hamiltonian G-space, let αg be a regular value with nonempty level, and suppose that Gα acts freely and properly on μ1(α). Then the reduced space Mα=μ1(α)/Gα has dimension

dimMα=dimMdimGdimGα.

In particular the value α enters the formula only through the dimension of its coadjoint stabilizer, and at α=0, where Gα=G, the formula specialises to dimM2dimG.

Facts & Assumptions

Given: ACω, a Hamiltonian G-space, a regular value α with nonempty level, and a free proper Gα-action on the level.

[A1]

ACω is countable choice; it is used only through the reduction and fundamental-field suppliers.

[F1]

Mα is the quotient of μ1(α) by the free proper Gα-action. Marsden--Weinstein--Meyer symplectic reduction.

[F2]

Regularity of α means dμp is surjective at every p in the level, so dimμ1(α)=dimMdimg. Regularity of a moment map is equivalent to local freeness, The differential of the moment map and the orbit-orthogonal identity.

[F3]

Quotienting a manifold by a free proper Gα-action lowers the dimension by dimGα. Marsden--Weinstein--Meyer symplectic reduction.

[F4]

The coadjoint stabilizer of 0 is G, and dimGα=dimgα. The coadjoint representation, action and orbits.

Proof

technique · direct
1.1

By [F2] the level has dimension dimMdimg.

F2given
2.1

By [F3] the quotient by the free proper Gα-action subtracts dimGα, so dimMα=dimMdimgdimGα=dimMdimGdimGα, using that a Lie group and its Lie algebra have equal dimension.

step 1.1F1F3
3.1

For α=0 the coadjoint action is linear, so every group element fixes 0 and G0=G by [F4]; the formula then reads dimM0=dimM2dimG, consistent with the zero-level corollary.

step 2.1F4A1

Depends on

Used by

Dependency tree · two levels

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