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Marsden--Weinstein--Meyer symplectic reduction
Statement
Assume . Let be a Hamiltonian -space, let be a regular value of , and suppose that the coadjoint stabilizer acts freely and properly on the level . Put
with the quotient structure, and let be the inclusion. Then is a smooth manifold and there is a unique symplectic form on satisfying
The pair is the symplectic reduction of at .
Facts & Assumptions
Given: , a Hamiltonian -space with moment map , a regular value , and a free proper -action on the level.
is countable choice; it is used only through the fundamental-field, level-set and quotient suppliers cited below.
If is nonempty, it is an embedded submanifold with , and is a smooth two-form on it. If it is empty, it is the empty smooth manifold and all pointwise tangent assertions below are vacuous. A regular level set is an embedded submanifold, The tangent space of a regular level set is the kernel.
Since acts freely and properly on , the quotient is a smooth manifold and is a smooth surjective submersion. Free proper action quotient manifold.
preserves the level and acts by restrictions of the symplectic action, which preserves . The moment level is invariant under the coadjoint stabilizer, Symplectic and Hamiltonian Lie-group actions.
On the level, for every , and the image of this subspace under is zero. The characteristic kernel on a regular moment level, Tangent space of a free proper quotient.
A -invariant horizontal form on the free proper -manifold descends to a unique form on ; a form on with zero pullback is zero. An invariant horizontal form on a free proper quotient descends uniquely.
Proof
If the level is empty, its quotient is the empty smooth manifold and the unique two-form on it is closed and nondegenerate vacuously, so the conclusion holds. Henceforth suppose the level is nonempty. The restricted form is -invariant: for the action preserves the level by [F3], so is a diffeomorphism of the level with , and because preserves .
The restricted form is horizontal for the -action: by [F4] each vertical vector , , lies in the kernel of , so any contraction of with a vertical entry vanishes.
By the descent lemma [F5] applied to the free proper -action on the level, there is a unique two-form on with .
Closedness: by [F6]; a form on the base with zero pullback vanishes by [F5], so .
Nondegeneracy: let with for all . Choose with ; since restricted to the level is a submersion, every is a lift of some , so for all . Hence by [F4], and therefore by [F4]. Thus is pointwise nondegenerate.
Steps 3.1 and 3.2 show that is closed and nondegenerate, hence symplectic on the manifold of [F2]; step 2.1 gives existence and uniqueness of the form with .
Depends on
- A regular level set is an embedded submanifold
- The tangent space of a regular level set is the kernel
- Free proper action quotient manifold
- Tangent space of a free proper quotient
- The characteristic kernel on a regular moment level
- The moment level is invariant under the coadjoint stabilizer
- An invariant horizontal form on a free proper quotient descends uniquely
- Regular and critical points and values
- Symplectic form and symplectic manifold
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Symplectic and Hamiltonian Lie-group actions
Used by
- Zero-level symplectic reduction and the dimension formula Corollary
- The zero angular-momentum level has nonfree points and no regular reduction Counterexample
- Complex projective space as a circle symplectic reduction Example
- Cotangent reduction for a principal bundle at zero Example
- Grassmannians from unitary symplectic reduction Example
- Weighted circle actions and weighted projective singular quotients Example
- Every value of a moment map gives a smooth symplectic quotient False statement
- Invariant Hamiltonians descend to reduced Hamiltonians Proposition
- Reduction commutes with products Proposition
- The dimension of a regular reduced space at a nonzero value Proposition
- The shifting trick identifies reduction at a value with a zero reduction Proposition
- Nonregular or nonfree symplectic quotients need not be manifolds Remark
- Reduction in stages for free proper regular actions Theorem
Dependency tree · two levels
45 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Eckhard Meinrenken, Symplectic Geometry (standard reference, not scraped)
- Ana Cannas da Silva, Lectures on Symplectic Geometry (standard reference, not scraped)