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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedaudited 2026-09-22
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Marsden--Weinstein--Meyer symplectic reduction

Statement

Assume ACω. Let (M,ω,G,μ) be a Hamiltonian G-space, let αg be a regular value of μ, and suppose that the coadjoint stabilizer Gα acts freely and properly on the level μ1(α). Put

Mα:=μ1(α)/Gα,π:μ1(α)Mα,

with the quotient structure, and let ι:μ1(α)M be the inclusion. Then Mα is a smooth manifold and there is a unique symplectic form ωα on Mα satisfying

πωα=ιω.

The pair (Mα,ωα) is the symplectic reduction of (M,ω,μ) at α.

Facts & Assumptions

Given: ACω, a Hamiltonian G-space with moment map μ, a regular value α, and a free proper Gα-action on the level.

[A1]

ACω is countable choice; it is used only through the fundamental-field, level-set and quotient suppliers cited below.

[F1]

If μ1(α) is nonempty, it is an embedded submanifold with Tpμ1(α)=kerdμp, and ιω is a smooth two-form on it. If it is empty, it is the empty smooth manifold and all pointwise tangent assertions below are vacuous. A regular level set is an embedded submanifold, The tangent space of a regular level set is the kernel.

[F2]

Since Gα acts freely and properly on μ1(α), the quotient Mα is a smooth manifold and π is a smooth surjective submersion. Free proper action quotient manifold.

[F3]

Gα preserves the level and acts by restrictions of the symplectic action, which preserves ω. The moment level is invariant under the coadjoint stabilizer, Symplectic and Hamiltonian Lie-group actions.

[F4]

On the level, ker(ιω)p=Tp(Gαp) for every p, and the image of this subspace under dπp is zero. The characteristic kernel on a regular moment level, Tangent space of a free proper quotient.

[F5]

A Gα-invariant horizontal form on the free proper Gα-manifold μ1(α) descends to a unique form on Mα; a form on Mα with zero pullback is zero. An invariant horizontal form on a free proper quotient descends uniquely.

Proof

technique · direct
1.1

If the level is empty, its quotient is the empty smooth manifold and the unique two-form on it is closed and nondegenerate vacuously, so the conclusion holds. Henceforth suppose the level is nonempty. The restricted form ιω is Gα-invariant: for hGα the action ah preserves the level by [F3], so ahμ1(α) is a diffeomorphism of the level with ιahlevel=ahι, and (ahlevel)ιω=ιahω=ιω because ah preserves ω.

F1F3
1.2

The restricted form is horizontal for the Gα-action: by [F4] each vertical vector ξM(p), ξgα, lies in the kernel of (ιω)p, so any contraction of ιω with a vertical entry vanishes.

F4
2.1

By the descent lemma [F5] applied to the free proper Gα-action on the level, there is a unique two-form ωα on Mα with πωα=ιω.

step 1.1step 1.2F2F5
3.1

Closedness: π(dωα)=d(πωα)=d(ιω)=ι(dω)=0 by [F6]; a form on the base with zero pullback vanishes by [F5], so dωα=0.

step 2.1F5F6
3.2

Nondegeneracy: let vT[p]Mα with ωα(v,w)=0 for all wT[p]Mα. Choose v~Tpμ1(α) with dπpv~=v; since π restricted to the level is a submersion, every w~Tpμ1(α) is a lift of some w, so (ιω)p(v~,w~)=ωα(v,dπpw~)=0 for all w~Tpμ1(α). Hence v~ker(ιω)p=Tp(Gαp) by [F4], and therefore v=dπpv~=0 by [F4]. Thus ωα is pointwise nondegenerate.

step 2.1F4
4.1

Steps 3.1 and 3.2 show that ωα is closed and nondegenerate, hence symplectic on the manifold Mα of [F2]; step 2.1 gives existence and uniqueness of the form with πωα=ιω.

step 2.1step 3.1step 3.2F2A1

Depends on

Used by

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