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CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-01
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Transverse embedded submanifolds intersect in the expected codimension

Statement

If S,T⊆M are transverse embedded submanifolds of codimensions a and b, then S∩T is an embedded submanifold of codimension a+b. At each p∈S∩T,

Tp(S∩T)=TpS∩TpT.

Facts & Assumptions

Given: Embedded submanifolds S,T⊆M with S⋔T.

[F1]

Two embedded submanifolds are transverse exactly when their inclusion maps are transverse (Transverse embedded submanifolds).

[L1]

The transverse preimage theorem identifies the preimage tangent space with the inverse image of the target tangent space (The transverse preimage theorem).

Proof

technique · direct
1.1F1L1given

Let i:S↪M be the inclusion. By [F1], i⋔T. Since i−1(T)=S∩T, [L1] shows that S∩T is an embedded submanifold of S of codimension codim⁡MT=b.

2.1L1step 1.1algebra

Therefore codim⁡M(S∩T)=codim⁡MS+codim⁡S(S∩T)=a+b. The tangent-space formula from [L1] becomes Tp(S∩T)={v∈TpS:dip(v)∈TpT}=TpS∩TpT.

3.1step 2.1∎

Hence transverse embedded submanifolds intersect in the expected codimension.

Depends on

Used by

Dependency tree · two levels

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Sources