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Preimage orientation agrees with the local intersection sign

Statement

Let f:Y→M be transverse to a closed oriented embedded submanifold Z, with Y,M oriented, M boundaryless, and, if Y has boundary, f∣∂Y transverse to Z. Orient Qy=Tf(y)M/Tf(y)Z by the normal-first determinant isomorphism det⁡Qy⊗det⁡Tf(y)Z≅det⁡Tf(y)M: quotient lifts precede the tangent determinant of Z. Orient Ky=Tyf−1(Z) by the kernel-first exact-sequence convention det⁡TyY≅det⁡Ky⊗det⁡Qy, where df induces the quotient map. In complementary dimensions dim⁡Y+dim⁡Z=dim⁡M, the resulting point sign is the local oriented intersection sign. If Z={z} has positive point orientation, this sign is sgn⁡(dfy); reversing that point orientation reverses the intersection sign.

Facts & Assumptions

Given: Oriented Y,M,Z, a transverse f:Y→M, and y∈f−1(Z).

[F1]

The transverse preimage tangent is Ky={v:dfy(v)∈Tf(y)Z}; thus 0→Ky→TyY→Qy→0 is exact (The transverse preimage theorem, and Transverse preimages for maps from manifolds with boundary for a boundary source).

[F2]

Orientation rays and ordered product determinants are the conventions of Determinant-line orientations of finite-dimensional real vector spaces and Product orientations.

[F3]

In complementary dimensions the local sign compares (dfy,di):TyY⊕Tf(y)Z→Tf(y)M with its given orientations (The local oriented intersection sign).

[F4]

The local sign of an equidimensional regular preimage compares the supplied source and target determinant rays, including point signs in dimension zero (Local orientation sign of a regular preimage).

Proof

1.1F1F2givenconstruct

For the normal-first isomorphism, wedge lifts of a quotient determinant before a tangent determinant of Z. Replacing a lift by a tangent vector changes the wedge by zero, so this is independent of lifts. Similarly wedging a kernel determinant before lifts of a quotient determinant defines the kernel-first exact-sequence isomorphism in the statement; it is independent of lifts and smooth in local adapted frames. The given rays therefore determine a unique smooth orientation of K.

2.1F1F2F3step 1.1algebra

In complementary dimensions Ky=0. Take positive determinant elements u of TyY and w of Tf(y)Z. The sign ε of (dfyu)∧w relative to the ambient ray is exactly the local intersection sign. By the normal-first convention, df‾y(u) has sign ε relative to the quotient ray. In det⁡TyY=det⁡Ky⊗det⁡Qy, the chosen scalar ray of det⁡Ky=R must therefore have sign ε too, so that the product ray is the given source ray. This is precisely the point orientation of the fibre.

3.1F2F4step 2.1algebra∎

For a positively oriented point Z, the normal-first quotient ray is the ambient ray, so 2.1 gives sgn⁡(dfy) by [F4]. A negatively oriented point changes that quotient ray and hence the fibre sign. All computations use determinant elements rather than positive empty bases and therefore include dimension zero; no choice principle is needed.

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