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LemmaStatement: Literature-sourcedProof: AI-adapted
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A self-transverse immersion has no double points when n>2m

Statement

Assume ACω. Let f:Mm→Xn be a self-transverse immersion with n>2m. Then Δ2(f)=∅, so f is injective. No properness or compactness of M is used; in particular self-transversality, not genericity, is the hypothesis.

Facts & Assumptions

Given: Countable choice and a self-transverse immersion f:Mm→Xn with n>2m.

[F1]

Δ2(f)={(x,y)∈M×M∖ΔM:f(x)=f(y)} and Σ(f)=f(pr⁡1Δ2(f)) (Self-transverse immersions and the double point locus).

[L1]

For a self-transverse immersion f:Mm→Xn, if 2m−n<0 then Δ2(f)=∅ and Σ(f)=∅ (The double point locus has the expected dimension 2m−n).

[L2]

Transverse maps F:Ux→Ww, G:Zz→Ww with x+z<w have empty fibre product; in particular transverse embedded submanifolds whose dimensions sum to less than the ambient dimension do not meet (Negative expected dimension forces empty generic intersections).

[A1]

Countable choice is inherited from the transversality machinery used in [L1] and [L2]; this proof selects nothing (The Axiom of Countable Choice (ACω)).

Proof

technique · direct
1.1L1L2A1

The hypothesis n>2m is 2m−n<0, so clause 2 of [L1] applies to the self-transverse immersion f and gives Δ2(f)=∅ and Σ(f)=∅. The negative expected dimension is the instance of [L2] for the transverse pair (f×f, ΔX↪X×X), whose source dimensions 2m and n sum to less than the target dimension 2n exactly when 2m<n.

2.1F1step 1.1

By [F1] an element of Δ2(f) is a pair of distinct points with equal image; since Δ2(f)=∅ there are no such pairs, hence f(x)=f(y) implies x=y, that is, f is injective.

3.1step 1.1step 2.1∎

Therefore every self-transverse immersion from an m-manifold into an n-manifold with n>2m is injective, without any compactness or properness hypothesis and with self-transversality in place of genericity.

Depends on

Used by

Dependency tree · two levels

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Sources