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Negative expected dimension forces empty generic intersections

Statement

Let f:Xx→Mn and g:Zz→Mn be smooth maps with x+z<n. If f and g are transverse, then X×MZ=∅. In particular, if Aa,Bb⊆Mn are transverse embedded submanifolds with a+b<n, then A∩B=∅. For the perturbation conclusion assume ACω and fix a closed embedded submanifold Z⊆M with dim⁡X+dim⁡Z<n. Every strong smooth neighbourhood of f contains a map transverse to Z (Strong Whitney approximation by transverse maps), hence disjoint from Z; a disjoint homotopic map is supplied by The transversality homotopy theorem. The cited approximation theorem concerns a fixed closed embedded submanifold, not an arbitrary map g.

Facts & Assumptions

Given: Smooth maps f:Xx→Mn and g:Zz→Mn with x+z<n, and the transverse case of the statement.

[F1]

f and g are transverse when dfa(TaX)+dgb(TbZ)=TyM at every pair (a,b) with f(a)=g(b)=y (Transverse smooth maps).

[F2]

Embedded submanifolds A,B⊆M are transverse when their inclusions are, that is, when TpA+TpB=TpM for every p∈A∩B (Transverse embedded submanifolds).

[F3]

Assume ACω: every strong smooth neighbourhood of a smooth map f contains a smooth map transverse to a fixed closed embedded submanifold (Strong Whitney approximation by transverse maps).

[F4]

Assume ACω: every smooth map is smoothly homotopic to a smooth map transverse to a fixed closed embedded submanifold (The transversality homotopy theorem, The Axiom of Countable Choice (ACω)).

Proof

technique · direct, by rank counting
1.1F1givenalgebra

Suppose there were (a,b) with f(a)=g(b)=y. Then [F1] gives TyM=dfa(TaX)+dgb(TbZ); the right side is the span of the images of vector spaces of dimensions x and z, so its dimension is at most x+z<n=dim⁡TyM, a contradiction. Hence there are no pairs with f(a)=g(b) and X×MZ=∅.

2.1F2step 1.1givenalgebra

If Aa,Bb⊆M are transverse embedded submanifolds with a+b<n and p∈A∩B, then applying 1.1 to the two inclusion maps gives TpA+TpB=TpM with left side of dimension at most a+b<n, a contradiction; hence A∩B=∅.

3.1F3F4step 1.1step 2.1∎

For the perturbation clause, let a strong neighbourhood of f and a closed embedded Z be given with dim⁡X+dim⁡Z<n; under the stated ACω, by [F3] the neighbourhood contains a smooth map transverse to Z, and by 1.1 that map misses Z, so after an arbitrarily small perturbation the intersection is empty; in the homotopy formulation the transverse representative is supplied by [F4]. The rank count itself uses no choice; ACω is consumed exactly by the approximation and homotopy theorems.

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