Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedverified 2026-09-23 (gpt-6-sol)
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The transversality homotopy theorem

Statement

Assume the Axiom of Countable Choice ACω (The Axiom of Countable Choice (ACω)). Let f:M→N be smooth and let Z⊆N be a closed embedded submanifold. Then f is smoothly homotopic to a smooth map g:M→N with g⋔Z.

Facts & Assumptions

Given: ACω, a smooth map f:M→N and a closed embedded submanifold Z⊆N.

[L1]

A smooth map admits a finite-dimensional perturbation family whose evaluation map is a submersion, hence transverse to Z (A tubular target produces a submersive finite-dimensional perturbation family).

[L2]

Under ACω, parametric transversality makes the bad-slice parameter set null (Parametric transversality). In a positive-dimensional ball its complement is dense; in a zero-dimensional ball a null subset is empty.

Proof

technique · direct
1.1L1givenchoose

By [L1], choose an open ball B⊆Rm and a smooth family F:M×B→N with F0=f such that the evaluation map F is transverse to Z.

2.1L2step 1.1

By [L2], the bad-slice parameter set is null in B. If m>0, its complement is dense and nonempty; if m=0, the null set is empty and a=0 is good. Choose a good parameter a.

3.1F1step 1.1step 2.1algebra∎

Because B is an open ball containing 0, the straight segment ta stays in B for all t∈I. Therefore H:M×I→N,H(x,t):=F(x,ta), is a smooth homotopy from f to g in the sense of [F1]. Thus f is smoothly homotopic to a smooth map transverse to Z.

Depends on

Used by

Dependency tree · two levels

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Sources