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The adjacency spectrum is an isomorphism invariant
Statement
If finite simple graphs and are isomorphic, then they have the same adjacency spectrum. In particular, cospectrality is an isomorphism invariant.
Facts & Assumptions
Given: Finite simple graphs and and an isomorphism .
A graph isomorphism is a bijection on vertices that preserves and reflects adjacency (Graph isomorphisms, automorphisms and graph complements).
The adjacency matrix records adjacency in the chosen vertex order (The adjacency matrix of a finite simple graph).
The adjacency spectrum is the multiset of roots of the adjacency characteristic polynomial, listed in weakly decreasing order (Adjacency spectrum, spectral radius, and cospectral graphs, For , the characteristic polynomial is when , with for the unique matrix).
Proof
Order the vertices of as and the vertices of as . In these orders the adjacency matrices and have the same entries, because [F1] and [F2] say that the entry is in either matrix exactly when and are adjacent in .
Since the two matrices are equal after a relabelling of the basis, they have the same characteristic polynomial and therefore the same spectrum by [F3]. This is exactly the claimed invariance.
Depends on
- The adjacency matrix of a finite simple graph
- Graph isomorphisms, automorphisms and graph complements
- Adjacency spectrum, spectral radius, and cospectral graphs
- For $A\in M_n(F)$, the characteristic polynomial is $\chi_A(x)=\det(xI_n-A)$ when $n\geq1$, with $\chi_A(x)=1$ for the unique $0\times0$ matrix
Used by
- Two cospectral graphs need not be isomorphic Counterexample
Dependency tree · two levels
13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- O. Pikhurko, Algebraic Methods in Combinatorics, Chapter 14 (standard reference, not scraped)