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PropositionStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
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Subalgebras, quotients, and finite products of nilpotent Lie algebras

Statement

Subalgebras and quotients of nilpotent Lie algebras are nilpotent. A nonempty finite direct product of nilpotent Lie algebras is nilpotent, and its class is the maximum of the factor classes. The empty direct product is the zero Lie algebra and has class 0.

Facts & Assumptions

Given: A Lie algebra g, a subalgebra h, an ideal i, and a finite family (gj)jJ of nilpotent Lie algebras.

[L1]

Nilpotence is termination of the lower central series (Lower central series and nilpotent Lie algebras).

[L2]

Nilpotency class is the least c with γc+1=0, and the zero algebra has class zero (Nilpotency class of a Lie algebra).

[L3]

The quotient map is a surjective Lie homomorphism (Quotient Lie algebras).

[L4]

Direct products have componentwise brackets, and an empty product is the zero Lie algebra (Direct products and direct sums of Lie algebras).

Proof

technique · direct
1.1

Induction gives γr(h)γr(g) for all r1, because [h,A][g,A]. Thus any lower-series term vanishing in g also vanishes in h.

givenL1algebra
1.2

If π:gg/i is the map in [L3], surjectivity and bracket preservation give γr(g/i)=π(γr(g)) by induction. Hence quotients inherit lower-series termination.

L1L3algebra
2.1

Componentwise bracketing in [L4] gives γr(jJgj)=jJγr(gj) for every r1. If J is nonempty, let c=maxjJcl(gj). For c=0 every factor, and hence the product, is zero. For c1, the product's (c+1)st term is zero, while its cth term is nonzero in a factor attaining the maximum. Thus [L2] gives class exactly c in either case. If J is empty, [L4] identifies the product with zero and [L2] gives class zero.

L1L2L4algebra

Depends on

Used by

Dependency tree · two levels

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Sources