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PropositionStatement: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
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The Lie bracket of left-invariant fields is left invariant

Statement

Assume ACω. If X and Y are left-invariant smooth vector fields on a Lie group G, then their Lie bracket [X,Y] is left invariant.

The countable-choice assumption is used exactly through the supplied invariant-field and smooth translation-trivialization results.

Facts & Assumptions

Given: ACω, a Lie group G, and left-invariant smooth vector fields X,Y on G.

[F1]

ACω is countable choice. The Axiom of Countable Choice (ACω).

[F2]

Left invariance means that every left translation carries the field to itself pointwise. Left- and right-invariant vector fields.

[F4]

Pushforward by a diffeomorphism preserves the Lie bracket. Diffeomorphism pushforward preserves Lie brackets.

Proof

technique · direct
1.1

Fix gG. By [F3], Lg is a diffeomorphism. The pointwise invariance identities in [F2] say exactly that (Lg)X=X and (Lg)Y=Y.

F2F3
2.1

Naturality [F4] and step 1.1 give (Lg)[X,Y]=[(Lg)X,(Lg)Y]=[X,Y]. Since g was arbitrary, [F2] says that [X,Y] is left invariant.

F2F4step 1.1
3.1

A Lie group is nonempty. In dimension zero all vector fields and brackets vanish, while dimension one requires no change. No metric or nondegeneracy condition occurs, and the group is boundaryless by convention. The stated ACω is inherited through [F2] and [F3]; fixing one arbitrary group element and applying bracket naturality makes no family selection. The proposition is a one-way closure statement, not a biconditional.

F1F2F3F4step 1.1step 2.1

Depends on

Used by

Dependency tree · two levels

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Sources