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The modular group of order p3 is extraspecial, of exponent p2 when p is odd

Statement

Let p be a prime and let Mp=A⋊αB be the modular group of order p3, with A=⟨a⟩ of order p2, B=⟨s⟩ of order p and sas−1=a1+p. Then ∣Mp∣=p3, the group is nonabelian,

Z(Mp)=[Mp,Mp]=⟨ap⟩

has order p, and Mp is extraspecial of exponent p2. At p=2 the group is the generalized dihedral group Dih⁡(C4).

Facts & Assumptions

Given: A prime p and the modular group Mp with its generators a and s.

[F1]

The modular group of order p3 is Mp=A⋊αB with A=⟨a⟩ of order p2, B=⟨s⟩ of order p, and sas−1=a1+p (The modular group of order p3 as a semidirect product Cp2⋊Cp).

[F2]

Z(G):={z∈G:zg=gz for every g∈G} (The center Z(G) of a group).

[F3]

For g,h∈G the commutator is [g,h]:=ghg−1h−1 (Commutators [g,h]=ghg−1h−1 and the commutator subgroup [G,G]).

[F4]

For a finite group G, exp⁡(G)=min⁡{n∈N:n>0 and gn=e for every g∈G} (The exponent of a finite group).

[L1]

In N⋊αH the sets Nˉ={(n,1)} and Hˉ={(1,h)} are subgroups, Nˉ is normal, Nˉ∩Hˉ={(1,1)}, every element has a unique factorisation (n,1)(1,h), and (1,h)(n,1)(1,h)−1=(αh(n),1) (The canonical copy of N is normal, the canonical copy of H is a complement, and conjugation induces the action).

[L2]

The class of 1+p in Z/p2 is a unit of multiplicative order p, and (1+p)k=1+kp (Raising to the power 1+p is an automorphism of order p of a cyclic group of order p2).

[L3]

For a finite p-group P the following are equivalent: P is extraspecial; P is nonabelian, ∣Z(P)∣=p and P/Z(P) is elementary abelian; P is nonabelian and Z(P)=P′=Φ(P) has order p (Three equivalent descriptions of an extraspecial p-group).

[L4]

For a finite group G and H≤G, ∣G∣=[G:H] ∣H∣ (Lagrange's theorem: ∣G∣=[G:H]∣H∣ for every subgroup H of a finite group G).

[L5]

If the quotient group G/Z(G) is cyclic, then G is abelian (If G/Z(G) is cyclic, then G is abelian).

[L6]

For N⊴G, the quotient G/N is abelian if and only if [G,G]⊆N (G/N is abelian if and only if [G,G]⊆N).

[L7]

An elementary abelian p-group is a finite abelian p-group in which every nonidentity element has order p (Elementary abelian p-groups).

[L8]

For n≥1, Dih⁡(Cn)=Cn⋊C2 where the nonidentity element of C2 acts by inversion ( Dih⁡(Cn)=Cn⋊C2 with inversion action has order 2n and the dihedral relations).

Proof

technique · direct
1.1F1L1L9

Every element of Mp has a unique factorisation aisj with 0≤i<p2 and 0≤j<p, so ∣Mp∣=p2⋅p=p3 and Mp is a finite p-group generated by a and s.

1.2F1F3L2L10

The relation gives [s,a]=sas−1a−1=a1+pa−1=ap, and ap has order p because a has order p2.

1.3F1F2L1L2L10

The element ap is central: it commutes with a, and saps−1=(sas−1)p=a(1+p)p=ap+p2=ap.

2.1F1L2step 1.1

Mp is nonabelian, since sas−1=a1+p≠a: equality would give ap=1, contradicting that a has order p2.

2.2F3L6L9step 1.1step 1.2step 1.3

Modulo ⟨ap⟩ the images of a and s commute, by step 1.2, and they generate; so Mp/⟨ap⟩ is abelian and [Mp,Mp]≤⟨ap⟩. With ap=[s,a]∈[Mp,Mp] this gives [Mp,Mp]=⟨ap⟩, of order p.

3.1F2L4L5step 1.3step 2.1step 2.2

The centre contains ⟨ap⟩ and is not all of Mp; its order divides p3, and an order of p2 would leave a quotient of order p, necessarily cyclic, forcing Mp abelian. So Z(Mp)=⟨ap⟩ has order p and equals [Mp,Mp].

3.2F4L4L9step 1.1step 2.1

The exponent is p2: the element a has order p2, so the exponent is a multiple of p2 dividing p3; it is not p3, because an element of order p3 in a group of order p3 would generate it and make it cyclic, hence abelian.

4.1L3L4L5L6L7step 2.1step 3.1

The quotient Mp/Z(Mp) has order p2, is abelian because [Mp,Mp]=Z(Mp), and is not cyclic, so all of its nonidentity elements have order p and it is elementary abelian; by the second description in the characterisation Mp is extraspecial.

5.1F1L8L2step 1.1∎

At p=2 the relation reads sas−1=a3=a−1, so the action of B on A is inversion and M2 is by definition the semidirect product of a cyclic group of order four by a cyclic group of order two acting by inversion, which is Dih⁡(C4).

Remarks

The group is extraspecial at every prime and its exponent is p2 at every prime; what changes at p=2 is only that the resulting group already has a name, since inversion is the unique nontrivial power automorphism of a cyclic group of order four.

Depends on

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Sources