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The modular group of order is extraspecial, of exponent when is odd
Statement
Let be a prime and let be the modular group of order , with of order , of order and . Then , the group is nonabelian,
has order , and is extraspecial of exponent . At the group is the generalized dihedral group .
Facts & Assumptions
Given: A prime and the modular group with its generators and .
The modular group of order is with of order , of order , and (The modular group of order as a semidirect product ).
For the commutator is (Commutators and the commutator subgroup ).
For a finite group , (The exponent of a finite group).
In the sets and are subgroups, is normal, , every element has a unique factorisation , and (The canonical copy of is normal, the canonical copy of is a complement, and conjugation induces the action).
The class of in is a unit of multiplicative order , and (Raising to the power is an automorphism of order of a cyclic group of order ).
For a finite -group the following are equivalent: is extraspecial; is nonabelian, and is elementary abelian; is nonabelian and has order (Three equivalent descriptions of an extraspecial -group).
For a finite group and , (Lagrange's theorem: for every subgroup of a finite group ).
If the quotient group is cyclic, then is abelian (If is cyclic, then is abelian).
For , the quotient is abelian if and only if ( is abelian if and only if ).
An elementary abelian -group is a finite abelian -group in which every nonidentity element has order (Elementary abelian -groups).
For , where the nonidentity element of acts by inversion ( with inversion action has order and the dihedral relations).
is the smallest subgroup of containing (The subgroup generated by a subset, the cyclic subgroup , and cyclic groups).
For all one has (Exponent laws in a group: and for all , and when and commute).
Proof
Every element of has a unique factorisation with and , so and is a finite -group generated by and .
The relation gives , and has order because has order .
The element is central: it commutes with , and .
is nonabelian, since : equality would give , contradicting that has order .
Modulo the images of and commute, by step 1.2, and they generate; so is abelian and . With this gives , of order .
The centre contains and is not all of ; its order divides , and an order of would leave a quotient of order , necessarily cyclic, forcing abelian. So has order and equals .
The exponent is : the element has order , so the exponent is a multiple of dividing ; it is not , because an element of order in a group of order would generate it and make it cyclic, hence abelian.
The quotient has order , is abelian because , and is not cyclic, so all of its nonidentity elements have order and it is elementary abelian; by the second description in the characterisation is extraspecial.
At the relation reads , so the action of on is inversion and is by definition the semidirect product of a cyclic group of order four by a cyclic group of order two acting by inversion, which is .
Remarks
The group is extraspecial at every prime and its exponent is at every prime; what changes at is only that the resulting group already has a name, since inversion is the unique nontrivial power automorphism of a cyclic group of order four.
Depends on
- Special and extraspecial $p$-groups
- Three equivalent descriptions of an extraspecial $p$-group
- Raising to the power $1+p$ is an automorphism of order $p$ of a cyclic group of order $p^2$
- The modular group of order $p^3$ as a semidirect product $C_{p^2}\rtimes C_p$
- The canonical copy of $N$ is normal, the canonical copy of $H$ is a complement, and conjugation induces the action
- The exponent of a finite group
- The order $|G|$ of a finite group and the order $\operatorname{ord}(g)$ of an element, with $\operatorname{ord}(g) = \infty$ when no positive power of $g$ is the identity
- The center $Z(G)$ of a group
- Commutators $[g,h]=ghg^{-1}h^{-1}$ and the commutator subgroup $[G,G]$
- Lagrange's theorem: $|G|=[G:H]|H|$ for every subgroup $H$ of a finite group $G$
- If $G/Z(G)$ is cyclic, then $G$ is abelian
- $G/N$ is abelian if and only if $[G,G]\subseteq N$
- Elementary abelian $p$-groups
- $\operatorname{Dih}(C_n)=C_n\rtimes C_2$ with inversion action has order $2n$ and the dihedral relations
- The subgroup $\langle S \rangle$ generated by a subset, the cyclic subgroup $\langle g \rangle$, and cyclic groups
- Exponent laws in a group: $g^{m+n} = g^{m}g^{n}$ and $(g^{m})^{n} = g^{mn}$ for all $m, n \in \mathbb{Z}$, and $(gh)^{n} = g^{n}h^{n}$ **when $g$ and $h$ commute**
- The quotient group $G/N$ and coset product $(gN)(hN)=ghN$
- A finite $p$-group has order $p^n$ for a prime $p$ and some $n\in\mathbb N$
Used by
- Plus and minus type of an extraspecial p-group Definition
- The modular group of order 27 has exponent 9 and exactly three cyclic subgroups of order 9 Example
- For odd p, a central product of two modular groups of order p³ is a central product of a modular group with a Heisenberg group Lemma
- For each prime there are exactly two nonabelian groups of order p³ up to isomorphism Theorem
- For odd p and each n≥1 there are exactly two extraspecial groups of order p¹⁺²ⁿ, distinguished by their exponent Theorem
Dependency tree · two levels
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Sources
- M. van Beek, Topics in Finite p-Groups, Proposition 2.32(i) and 2.32(iv) (standard reference, not scraped)
- D. A. Craven, The Theory of p-Groups, Definition 3.3 (standard reference, not scraped)