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Whitehead's second lemma removes the infinitesimal equivariance obstruction for semisimple actions
Statement
Assume , connected , connected , and suppose an infinitesimal moment map is supplied for the action: that is, each closed one-form has a chosen Hamiltonian function , depending linearly on . If is finite-dimensional real semisimple, then there is a covector such that
is a coadjoint-equivariant moment map. Thus constants can be added to a supplied infinitesimal moment map to make it equivariant. The argument assumes the linear choice of Hamiltonians and does not prove that the component one-forms are exact; it removes only the obstruction to equivariance.
Facts & Assumptions
Given: , connected and , an infinitesimal moment map for the action, and a finite-dimensional real semisimple .
is countable choice; it is used through the moment-map, defect, and equivariance interfaces cited in [F1], [F2], and [F6].
The components satisfy for all . Moment map, component Hamiltonians and infinitesimal moment maps.
The nonequivariance defect is a constant on and is a Chevalley--Eilenberg two-cocycle with trivial coefficients. The nonequivariance defect of an infinitesimal moment map is a constant Lie-algebra two-cocycle.
For a finite-dimensional semisimple over a characteristic-zero field, for every finite-dimensional module , in particular for the trivial module. Second Whitehead lemma, Lie algebra cohomology, Simple, semisimple, and reductive Lie algebras.
With the zero-based convention, the Chevalley--Eilenberg differential of a one-cochain is ; hence means . Chevalley–Eilenberg differential.
Constants are Poisson-central: adding a constant to a function changes no Hamiltonian vector field and the Poisson bracket of a constant with any function vanishes. Poisson bracket on a symplectic manifold.
The defect vanishes identically on the connected manifold if and only if is coadjoint equivariant, and for connected the bracket identity is equivalent to equivariance. The nonequivariance defect of an infinitesimal moment map is a constant Lie-algebra two-cocycle, For connected groups, equivariance is equivalent to the moment-map Poisson bracket identity.
Proof
By [F1] the map is an infinitesimal moment map, so its defect from [F2] is a constant two-cocycle with trivial coefficients; identifying the trivial module with , [F3] gives .
Since represents the zero class and is a two-cocycle, it is a coboundary for some one-cochain , so for all by [F4].
Define , that is . Its components differ from those of by constants, so by [F5] the Poisson bracket is unchanged and the defect of is
The component moment equations hold for as well, because the components differ from those of by constants, which have zero differential.
Since on the connected manifold and is connected, [F6] shows that is coadjoint equivariant; combined with step 4.1, is an equivariant moment map.
Depends on
- The nonequivariance defect of an infinitesimal moment map is a constant Lie-algebra two-cocycle
- For connected groups, equivariance is equivalent to the moment-map Poisson bracket identity
- Second Whitehead lemma
- Lie algebra cohomology
- Chevalley–Eilenberg differential
- Simple, semisimple, and reductive Lie algebras
- Moment map, component Hamiltonians and infinitesimal moment maps
- Poisson bracket on a symplectic manifold
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
Used by
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Sources
- Ana Cannas da Silva, Lectures on Symplectic Geometry (standard reference, not scraped)
- Eckhard Meinrenken, Symplectic Geometry (standard reference, not scraped)