Alphabeta Math
RemarkSession-authored (Fable 5 assisted) sources checked 2026-07-26 not proved here
Recorded, not proved here. This statement is included so the library can refer to it honestly, with a citation to the literature. It is not proved anywhere in this library: the track that would prove it has not been developed here yet.

Absolutely continuous functions

Statement

A function F:[a,b]RF : [a,b] \to \mathbb{R} is absolutely continuous when for every ε>0\varepsilon > 0 there is δ>0\delta > 0 such that for every finite family of pairwise disjoint subintervals (a1,b1),,(aN,bN)(a_1, b_1), \dots, (a_N, b_N) of [a,b][a,b],

k=1N(bkak)<δ  k=1NF(bk)F(ak)<ε.\sum_{k=1}^{N} (b_k - a_k) < \delta \ \Longrightarrow \ \sum_{k=1}^{N} |F(b_k) - F(a_k)| < \varepsilon.

Write AC[a,b]AC[a,b] for the class of such FF. The inclusions

LipschitzAC[a,b]{continuous and of bounded variation}{continuous}\text{Lipschitz} \subsetneq AC[a,b] \subsetneq \{\text{continuous and of bounded variation}\} \subsetneq \{\text{continuous}\}

are all strict: xxx \mapsto \sqrt{x} on [0,1][0,1] is absolutely continuous but not Lipschitz; the Cantor function is continuous, increasing and of bounded variation but not absolutely continuous; and xxsin(1/x)x \mapsto x \sin(1/x) on (0,1](0,1], extended by 00, is continuous but not of bounded variation. AC[a,b]AC[a,b] is a vector space, closed under products, and FAC[a,b]F \in AC[a,b] has Luzin's property (N): it maps null sets to null sets.

Remarks

Partly proved elsewhere in this library. The elementary definition is Absolute continuity on a compact interval . The hierarchy C1LipschitzACCBVC^1\subseteq\mathrm{Lipschitz}\subseteq AC\subseteq C\cap BV and strictness witnesses are proved in C1C^1 implies Lipschitz, Lipschitz implies absolutely continuous, and absolutely continuous implies continuous and bounded variation and its companion examples. Closure under vector-space operations and products, Luzin's property (N), the sharp Lebesgue-integral FTC and the Banach–Zarecki characterisation remain unproved.

What would prove it. Absolute continuity implies bounded variation by a covering argument on [a,b][a,b]; property (N) follows from the definition applied to a cover of the null set by intervals of small total length; strictness of the inclusion at the Cantor function needs that cc maps a null set onto a set of measure 11, and that is a genuine measure statement. The real theorem about the class is The sharp fundamental theorem of calculus (absolute continuity) , and its characterisation without integrals is Banach-Zarecki theorem .

Which page it serves. The bounded variation and Riemann-Stieltjes page, which builds the theory of BV[a,b]BV[a,b], the Jordan decomposition into a difference of increasing functions, and the total variation function. Absolute continuity is the next class in that hierarchy and the one for which the Newton-Leibniz formula is exactly true, so the page can define it, place it in the hierarchy with the counterexamples above, and then must stop.

What is in scope on that page. The whole BVBV theory, the Jordan decomposition, the Cantor function as a continuous increasing non-constant function with derivative zero off a null set, and the elementary statement that absolutely continuous implies uniformly continuous and of bounded variation. What is not in scope is any statement whose formulation needs the Lebesgue integral.

Depends on

Used by

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Sources