Alphabeta Math
RemarkRemark: AI-generatedProof: Not applicableSession-authored (Fable 5 assisted)verified 2026-08-03 (gpt-5.6-sol-codex-subscription)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated — a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The conventions this page fixes: the empty intersection, where the counts live, the first index of every sum, and what the declared prerequisites do not supply

This item is the page's ledger: every convention the page fixes, with the item that fixes it, and a statement of what this page's declared prerequisites do not supply. It continues Conventions fixed on this page, and what counting is deliberately not done here, the same kind of ledger for the page finite-counting-and-binomial-coefficients, which is this page's declared prerequisite.

Conventions fixed here

The empty intersection is the ambient set, and the ambient set is part of the data. A finite family (Ai)iI(A_i)_{i \in I} of subsets of a finite set XX, the intersections AJA_J for JIJ \subseteq I, and the convention A=XA_\varnothing = X fixes a finite XX together with the family (Ai)iI(A_i)_{i \in I} and stipulates A=XA_\varnothing = X. This is a stipulation and not a theorem: for nonempty JJ the intersection is determined by the family, and for J=J = \varnothing the description "belongs to every AiA_i with iJi \in J" is satisfied by everything, so it determines nothing without an ambient set to be relative to. The clause supplies the J=J = \varnothing term in the complementary form of Inclusion and exclusion: ιiIAi=JI(1)J+1ιAJ\iota\lvert\bigcup_{i \in I} A_i\rvert = \sum_{\varnothing \ne J \subseteq I}(-1)^{\lvert J\rvert + 1}\,\iota\lvert A_J\rvert, together with the complementary form counting the elements in none of the AiA_i and in later sieves whenever an intersection must also be identified at the empty subfamily.

Counts live in N\mathbb{N}; every alternating identity lives in R\mathbb{R}. A cardinality is a natural number, a natural number here is a set, and a set is not an element of R\mathbb{R}. Every identity on this page that uses a negative summand, and every one that divides counts, is therefore stated in R\mathbb{R} with the counts carried across by the canonical natural ι\iota (The canonical natural ι(n)=n1F\iota(n) = n \cdot 1_F of a field), and read back through the injectivity of ι\iota where the conclusion is about natural numbers. Truncated natural differences such as n1n-1 and n2n-2 remain in N\mathbb N and are not negative summands.

Every index range starts at 00, and the lower-bound hypotheses on this page exist only because of it. j<m+1(1)jι(tj)=(1)mι(t1m)\sum_{j<m+1}(-1)^{j}\,\iota\binom{t}{j} = (-1)^{m}\,\iota\binom{t-1}{m} for every t1t \ge 1 and every mm carries t1t \ge 1; without it the identity fails at t=0t = 0 and m=1m = 1. ι(Dn)=ι(n)ι(Dn1)+(1)n\iota(D_n) = \iota(n)\,\iota(D_{n-1}) + (-1)^{n} for n1n \ge 1, and Dn=(n1)(Dn1+Dn2)D_n = (n-1)(D_{n-1} + D_{n-2}) for n2n \ge 2 carries n1n \ge 1 in its first clause, because the identity n!=(n1)!nn! = (n-1)!\cdot n that proves it fails at n=0n = 0 under the truncated difference, and n2n \ge 2 in its second, because that clause applies the first one at n1n-1. m/n\lceil m/n \rceil for naturals mm and n1n \ge 1: the least qNq \in \mathbb{N} with mnqm \le n q carries n1n \ge 1, without which the set it takes a least element of can be empty.

00=10^{0} = 1, and the place it is spent is named. The convention is the base clause of the recursion in Exponentiation of natural numbers, mnm^{n}, and its agreement with the integer power in R\mathbb{R}, not an import. In The number of surjections from an nn-element set onto a kk-element set is i<k+1(1)i(ki)(ki)n\sum_{i<k+1}(-1)^{i}\binom{k}{i}(k-i)^{n}, read in R\mathbb{R} through ι\iota it is what makes the formula correct at n=0n = 0 and k=0k = 0, where the empty function is the unique surjection \varnothing \to \varnothing and the formula returns ι(00)\iota(0^{0}). At n=0n = 0 with k1k \ge 1 the same formula returns the full alternating row sum, which vanishes only because k1k \ge 1; and at k=0k = 0 with n1n \ge 1 it returns ι(0n)\iota(0^{n}), which is 00 for the same reason read the other way. Powers of 1-1 are the real powers of Integer powers ama^m throughout, since 1-1 is not a natural number.

A sum over a finite index set is what all of this is written in. The sum iSai\sum_{i \in S} a_i over a finite index set, and its product form is the notion used for every sum whose index set is a set of subsets, a set of elements or a relation's fibre family, and its value is independent of the enumeration chosen. The facts about it that are used constantly and are not clauses of it are the bridge ι(N)=Rι\iota\big(\sum^{\mathbb{N}}\big) = \sum^{\mathbb{R}}\iota over such an index set, and the additivity, scaling and monotonicity laws over such an index set. Both are derived, in the Facts of the items that use them, from the corresponding clauses about a sum over an initial segment together with the enumeration that defines the sum over an index set.

A relation, not a matrix. A relation RX×YR \subseteq X \times Y between finite sets, its row fibres RxR_x and its column fibres RyR^y sets up a subset of a product of two finite sets, its two fibre families and their slice partitions. Double counting: xXRx=R=yYRy\sum_{x \in X}\lvert R_x\rvert = \lvert R\rvert = \sum_{y \in Y}\lvert R^y\rvert for a relation between finite sets states the resulting equality of the two fibre sums with the size of the relation, and nothing more.

Fibres of a function. If A>kB\lvert A\rvert > k\lvert B\rvert then every f:ABf : A \to B has a fibre with more than kk elements, and for nonempty BB some fibre has at least A/B\lceil \lvert A\rvert / \lvert B\rvert\rceil elements is stated about the fibres f1[{b}]f^{-1}[\{b\}] of a function between finite sets. Its two clauses are one argument: the ceiling form is the counting form applied at the single index below the ceiling, which is why the ceiling was defined by minimality.

What this page's declared prerequisites do not supply

Each of the following is a statement about what this page may cite, and about nothing else.

  • No floor and no ceiling as general notions, and no division with remainder. m/n\lceil m/n \rceil for naturals mm and n1n \ge 1: the least qNq \in \mathbb{N} with mnqm \le n q defines only the least qq with mnqm \le nq, for naturals mm and n1n \ge 1. It is not defined for a real argument, it produces no remainder, and nothing here extends it.

  • No divisibility. No result on this page is stated in terms of one natural number dividing another, and no argument uses such a relation.

  • No graph vocabulary. Nothing among this page's declared prerequisites defines a graph, a vertex or an edge. The results that would usually be stated about graphs are stated instead about a finite set carrying a symmetric irreflexive relation, which is exactly what their proofs use.

  • No probability. Nothing among this page's declared prerequisites defines a probability space, a measure or an expectation. The averaging principle is a statement about a quotient of two counts, and the hat-check ratio on the companion page is a quotient of two counts; neither is called a probability and neither is treated as one.

  • No symmetric group. The derangement number DnD_n: the number of bijections of an nn-element set with no fixed point counts a set of bijections. No group structure on that set is defined or used.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 93 results over 28 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources