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A functor between additive categories is additive exactly when it preserves finite biproducts

Statement

For a functor between additive categories, the following are equivalent:

  1. the functor is additive;
  2. the functor preserves finite biproducts.

Facts & Assumptions

Given: A functor F:CD between additive categories.

[L1]

Additive functors preserve finite biproducts (An additive functor preserves finite biproducts).

[L2]

Additive categories are preadditive with finite biproducts (Additive category).

[L3]

In a preadditive category, finite products are automatically biproducts (In a preadditive category, a finite product is automatically a biproduct).

[L4]

In an additive category, the preadditive hom-group law is a bilinear commutative-monoid enrichment compatible with the finite biproduct diagrams. Indeed, product uniqueness gives f,g=i1f+i2g, and bilinearity then gives f,g=f+g. By uniqueness this is the canonical biproduct addition (The commutative-monoid enrichment of a category with finite biproducts is unique).

Proof

technique · direct
1.1

The implication from 1 to 2 is exactly [L1].

L1
1.2

Assume F preserves finite biproducts. In an additive category, for parallel morphisms f,g:AB, the pairing into BB is the unique morphism f,g with projections f and g, and the codiagonal is the unique morphism B:BBB with both composites equal to 1B. Since F preserves the relevant biproducts, it preserves those pairings and codiagonals.

L2L3
1.3

By [L4], the hom-group addition in an additive category is the canonical biproduct addition. [L2, L4, step 1.2] f+g=Bf,g. Step 1.2 therefore gives F(f+g)=F(B)F(f,g)=FBFf,Fg=Ff+Fg. So F is additive.

L2L4step 1.2
2.1

Steps 1.1 and 1.3 prove the equivalence.

step 1.1step 1.3

Depends on

Used by

Dependency tree · two levels

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Sources