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A natural transformation of functors induces a unique morphism of their ends and of their coends
Statement
Let be functors and let be a natural transformation (Natural transformation and its components); a wedge is a dinatural transformation from a constant functor (Dinatural transformation between functors on ).
If and have ends and (The end and the coend of a functor ), then a natural transformation induces a unique morphism of ends: there is exactly one morphism satisfying
If and have coends and , there is exactly one morphism satisfying for every .
Moreover , and whenever and are natural and all three ends exist.
Facts & Assumptions
Given: Functors , a natural transformation , and ends and coends of and of where these are asserted to exist.
An end of is a terminal object of the category of wedges over and a coend an initial object of the category of cowedges under ; in short, an end is a terminal wedge and a coend an initial cowedge, and the universal property says that every wedge factors through the end by exactly one morphism (The end and the coend of a functor ).
A wedge from to is a dinatural transformation from a constant functor to : a family with for every ; dually a cowedge from to is a family with (Wedges and cowedges, and the categories they form).
A natural transformation is a family such that every satisfies the naturality equation (Natural transformation and its components).
A dinatural transformation is a family such that every satisfies , the equation displayed by the hexagon (Dinatural transformation between functors on ).
Proof
The family is a wedge from to : naturality of at gives , naturality at gives , and the wedge equation for gives , so both sides of the wedge equation for equal composed with that common morphism.
Since is a terminal wedge, the wedge of step 1.1 factors through it by exactly one morphism, which is the asserted with for every .
Taking , and , the identity of satisfies the defining equation of step 2.1, and that equation has exactly one solution, so .
For and with all three ends present, both and satisfy , and that equation has exactly one solution, so the two agree.
For coends, the family is a cowedge under : naturality of at and at rewrites both sides of its cowedge equation as and , which agree by the cowedge equation for ; initiality of then gives exactly one with . The induced morphism runs from the coend of to the coend of , in the same direction as , and the argument is written out here rather than left to duality because the universal property used is initiality rather than terminality.
Remarks
The two functor laws in steps 3.1 and 3.2 are proved from uniqueness alone and use nothing about beyond its defining equation. So on any full subcategory of functors all of whose objects have a chosen end, the assignment with is a functor; making that statement precise for a family of parameters, where the choice has to be made for every parameter value at once, is A chosen family of ends is the object part of exactly one functor making the counit natural in the parameters.
Depends on
Used by
Dependency tree · two levels
10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- F. Loregian, (Co)end Calculus (arXiv:1501.02503v7), Remark 1.1.7 (standard reference, not scraped)
- G. M. Kelly, Basic Concepts of Enriched Category Theory (TAC Reprints 10), §2.1 (standard reference, not scraped)