Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A wide coherent blockade contains a blockade-rainbow copy of a forest

Statement

Let F be a forest on vertices u1,,um, and let B=(B1,,Bm) be a blockade in a graph G. Suppose that for every distinct i,j[m],

  1. Bi is complete to Bj when uiujE(F); and
  2. Bi is anticomplete to Bj when uiujE(F).

Then G contains a B-rainbow induced copy of F.

Facts & Assumptions

Given: A forest F on vertices u1,,um, a graph G, and a blockade B=(B1,,Bm) satisfying the two displayed cross-block conditions.

[L1]

A B-rainbow induced copy of F means an induced copy lying in V(B) and using at most one vertex from each block (A blockade-rainbow induced copy).

[F1]

Every block of a blockade is nonempty (Blockades, their length, their width, and their support).

Proof

technique · direct
1.1

By [F1], choose vertices xiBi for every i[m]. Let X:={x1,,xm}. Because the blocks are pairwise disjoint, these m vertices are distinct.

F1choosegiven
2.1

For distinct i,j[m], the hypothesis says that xi and xj are adjacent exactly when ui and uj are adjacent in F. Hence the map uixi is an adjacency-preserving and nonadjacency-preserving bijection from V(F) to X, so G[X] is an induced copy of F.

step 1.1given
3.1

The copy G[X] lies in V(B) and uses exactly one vertex from each block, so [L1] shows that it is B-rainbow.

step 2.1L1

Depends on

Used by

Dependency tree · two levels

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Sources