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Artin induction for rational characters

Statement

Let G be a finite group, and let x∈RQ(G) in the sense of The rational representation ring RQ(G) and rational-valued class functions. Then:

  1. x is a rational linear combination of characters induced from cyclic subgroups of G.
  2. Equivalently, the controlled multiple ∣G∣x lies in the cyclic induction subgroup Icyc(G).

Facts & Assumptions

Given: A finite group G and an element x∈RQ(G).

[F1]

The cyclic induction subgroup Icyc(G) is an ideal of R(G) (The cyclic induction subgroup is an ideal of the character ring).

[F2]

The trivial character satisfies an Artin relation ∣G∣1G=∑iaiInd⁡CiG1Ci with Ci≤G cyclic and ai∈Z (A positive integer multiple of the trivial character is an integral combination of cyclic permutation characters).

[F3]

The projection formula says (Ind⁡HGχ)ψ=Ind⁡HG(χ Res⁡HGψ) (Induction and restriction satisfy the projection formula on character rings).

[A1]

If a finite-dimensional representation is defined over Q, then its restriction to a subgroup is again defined over Q.

Proof

technique · direct
1.1F1F2givenalgebra

By [F2], choose cyclic subgroups Ci≤G and integers ai with ∣G∣1G=∑iaiInd⁡CiG1Ci. Multiplying by x in R(G) gives ∣G∣x=∑iai(Ind⁡CiG1Ci)x. Because [F1] makes Icyc(G) an ideal containing each Ind⁡CiG1Ci, this already shows ∣G∣x∈Icyc(G).

2.1F3A1step 1.1algebra

Applying [F3] to each summand of step 1.1 yields ∣G∣x=∑iaiInd⁡CiG(Res⁡CiGx). By [A1], each Res⁡CiGx again lies in the rational representation ring of the cyclic subgroup Ci. This identity is an explicit expression of ∣G∣x as a sum of characters induced from cyclic subgroups.

3.1step 2.1algebra

Dividing the identity of step 2.1 by ∣G∣ expresses x as a rational linear combination of characters induced from cyclic subgroups of G. This is claim 1.

4.1F1step 1.1step 3.1algebra∎

Conversely, if x is any rational linear combination of characters induced from cyclic subgroups, then multiplying by a common positive denominator places that multiple of x in Icyc(G). Step 1.1 shows that one may take the specific controlled denominator ∣G∣, so claims 1 and 2 are equivalent.

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Sources