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PropositionStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-30
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Induction and restriction satisfy the projection formula on character rings

Statement

Let G be a finite group, let H≤G, let χ∈R(H), and let ψ∈R(G). Then

Ind⁡HG ⁣(χ⋅Res⁡HGψ)=(Ind⁡HGχ)⋅ψ

in the character ring R(G).

Facts & Assumptions

Given: A finite group G, a subgroup H≤G, a complex character χ of H, and a complex character ψ of G.

[F1]

Frobenius' formula gives Ind⁡HGχ(g)=1∣H∣∑x−1gx∈Hχ(x−1gx) (Frobenius' formula for the character of an induced representation).

[F2]

Characters multiply on tensor products, and addition is pointwise (Characters add on direct sums, multiply on tensor products, and conjugate on duals).

[F4]

The character ring is the Z-span of ordinary characters, with addition and multiplication extending Z-bilinearly (Virtual characters and the character ring R(G) of a finite group).

[F5]

Frobenius reciprocity identifies induction and restriction as adjoint operations on characters (Frobenius reciprocity for complex characters).

Proof

technique · direct
1.1F1F4given

For an honest pair of characters χ and ψ and any g∈G, [F1] gives Ind⁡HG(χRes⁡HGψ)(g)=1∣H∣∑x∈G, x−1gx∈Hχ(x−1gx)ψ(x−1gx).

2.1F1F3step 1.1algebra

Since ψ is a class function by [F3], ψ(x−1gx)=ψ(g) for each summand of step 1.1. Factoring that constant out of the finite sum and applying [F1] again yields Ind⁡HG(χRes⁡HGψ)(g)=ψ(g)Ind⁡HGχ(g)=((Ind⁡HGχ)ψ)(g).

3.1F4step 2.1algebra

So the identity holds for ordinary characters. By [F4], both induction and multiplication extend Z-bilinearly to virtual characters, so the same pointwise identity holds for all χ∈R(H) and ψ∈R(G).

4.1F2F5step 3.1∎

This pointwise equality is the projection formula in R(G), and [F2] identifies the pointwise product on the right with the character-ring product coming from tensor products. The adjoint viewpoint from [F5] is compatible with it, but step 3.1 already proves the formula.

Depends on

Used by

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Sources