Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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General Ascoli theorem for locally compact Hausdorff domains and metric targets

Statement

Assume the Axiom of Choice. Let X be a locally compact Hausdorff space, let Y be a metric space, and let F⊆C(X,Y). The compact-open closure of F is compact if and only if F is equicontinuous and pointwise relatively compact.

Facts & Assumptions

Given: Choice, a locally compact Hausdorff space X, a metric space Y, and F⊆C(X,Y).

[L1]

Under Choice, equicontinuity and pointwise relative compactness imply compactness of the compact-open closure (Under Choice, equicontinuity and pointwise relative compactness give compact compact-open closure).

[L2]

A compact compact-open family on a locally compact Hausdorff domain is equicontinuous (A compact compact-open family is equicontinuous on a locally compact Hausdorff domain).

[L3]

Every compact compact-open family is pointwise relatively compact (Every compact compact-open family is pointwise relatively compact).

Proof

technique · direct
1.1L2

Suppose the compact-open closure F‾co is compact. By [L2] it is equicontinuous, and restricting its common neighbourhood estimates to F shows that F is equicontinuous.

1.2L3L4

By [L3], F‾co is pointwise relatively compact. For each x, the closure of F(x) is a closed subset of the compact closure of F‾co(x), hence is compact by [L4]; thus F is pointwise relatively compact.

1.3L1

Conversely, if F is equicontinuous and pointwise relatively compact, [L1] says directly that its compact-open closure is compact.

2.1step 1.1step 1.2step 1.3∎

Steps 1.1--1.2 and 1.3 prove the two directions of the equivalence.

Depends on

Used by

Dependency tree · two levels

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Sources