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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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General Ascoli theorem for locally compact Hausdorff domains and metric targets

Statement

Assume the Axiom of Choice. Let X be a locally compact Hausdorff space, let Y be a metric space, and let FC(X,Y). The compact-open closure of F is compact if and only if F is equicontinuous and pointwise relatively compact.

Facts & Assumptions

Given: Choice, a locally compact Hausdorff space X, a metric space Y, and FC(X,Y).

[L1]

Under Choice, equicontinuity and pointwise relative compactness imply compactness of the compact-open closure (Under Choice, equicontinuity and pointwise relative compactness give compact compact-open closure).

[L2]

A compact compact-open family on a locally compact Hausdorff domain is equicontinuous (A compact compact-open family is equicontinuous on a locally compact Hausdorff domain).

[L3]

Every compact compact-open family is pointwise relatively compact (Every compact compact-open family is pointwise relatively compact).

Proof

technique · direct
1.1

Suppose the compact-open closure Fco is compact. By [L2] it is equicontinuous, and restricting its common neighbourhood estimates to F shows that F is equicontinuous.

L2
1.2

By [L3], Fco is pointwise relatively compact. For each x, the closure of F(x) is a closed subset of the compact closure of Fco(x), hence is compact by [L4]; thus F is pointwise relatively compact.

L3L4
1.3

Conversely, if F is equicontinuous and pointwise relatively compact, [L1] says directly that its compact-open closure is compact.

L1
2.1

Steps 1.1--1.2 and 1.3 prove the two directions of the equivalence.

step 1.1step 1.2step 1.3

Depends on

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