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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-10
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Boone special word equivalence

Statement

Assume AC. For every special word Σ=X#qjY, with X,Y positive tape words, possibly empty, W(Σ)=1 in BΣ=XqjY=q in Γ.

Facts & Assumptions

Given: A positive special word Σ in the stated domain.

[F1]

A positive semigroup history Σ=q gives Σ=LqR and W(Σ)=1. (Boone positive history pushing)

[F2]

W(Σ)=1 gives LΣR=q in the embedded G2 for freely reduced auxiliary words. (Boone commutator extracts an auxiliary history)

[F3]

Such an auxiliary equation for a special word gives Σ=q in Γ. (Boone positive history reconstruction)

[A1]

Assume AC for the HNN arguments in these facts. (The Axiom of Choice)

Proof

1.1

Suppose W(Σ)=1. The given positive special spelling satisfies the domain of [F2], so it supplies auxiliary L,R with equality in G2. This is exactly the group and equation required by [F3], and that fact yields Σ=q in Γ.

F2F3A1given
2.1

Conversely, suppose Σ=q. Equality in the presented semigroup is a finite symmetric history, and the special spelling has positive contexts. Thus [F1] applies and gives W(Σ)=1. The two implications include X=Y=ε; for qj=q they reduce to the defining commutation of k and q1tq. This proves the stated equivalence on precisely the positive special-word domain.

F1A1step 1.1given

Source locator

Rotman, printed p.431, Lemma 12.7; proofs on pp.432–433 and pp.438–447. No equivalence for arbitrary signed tape words is asserted here.

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Sources