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The Caccioppoli inequality for weak elliptic solutions

Statement

Assume Countable Choice. Let Ω⊆Rn be open, n≥1, K∈{R,C}, let L,a be as in Uniformly elliptic divergence-form operators and their sesquilinear forms with ellipticity constant θ and coefficient bounds Ma,Mb,Mc, let f∈Lloc2(Ω) and let u∈H1(Ω;K) be a local weak solution of Lu=f on Ω (Local weak solutions of a divergence-form operator). For every ball BR(x0)⋐Ω and every 0<r<R there is a constant C=C(n,θ,Ma,Mb,Mc) with ∫Br(x0)∣Du∣2 dx≤C(1(R−r)2∫BR(x0)∣u∣2 dx+∫BR(x0)∣u∣2 dx+∫BR(x0)∣f∣2 dx). No regularity of the coefficients beyond measurability and essential boundedness is used, and the estimate is uniform in the localisation. When f=0 the estimate is the energy inequality for a locally weak harmonic class.

Facts & Assumptions

Given: Countable Choice; an open set Ω⊆Rn with n≥1; a scalar field K∈{R,C}; coefficients aij,bi,c and the form a(⋅,⋅) of Uniformly elliptic divergence-form operators and their sesquilinear forms with ellipticity constant θ and bounds Ma,Mb,Mc; a class f∈Lloc2(Ω); a local weak solution u∈H1(Ω) of Lu=f; a ball BR(x0)⋐Ω; and a radius 0<r<R; the standard smooth step σ of The standard smooth step function is fixed once and for all, with S:=∥σ′∥L∞(R).

[F1]

The form is well defined on H1(Ω) and bounded: ∣a(w,z)∣≤(nMa+nMb+Mc)∥w∥H1∥z∥H1 for w,z∈H1(Ω), the value depends only on the H1 classes, and the form is linear in the first and conjugate-linear in the second slot. (The elliptic form is well defined and bounded on H1, Uniformly elliptic divergence-form operators and their sesquilinear forms)

[F2]

Uniform ellipticity: Re⁡(∑i,jaij(x)ξjξi‾)≥θ∣ξ∣2 for almost every x∈Ω and every ξ∈Cn; the coefficient bounds ∣aij∣≤Ma, ∣bi∣≤Mb, ∣c∣≤Mc hold almost everywhere. (Uniformly elliptic divergence-form operators and their sesquilinear forms)

[F3]

The local weak equation is equivalent to a(u,v)=∫Ω2f v‾ dx for every bounded open Ω2⋐Ω and every v∈H01(Ω2), and every class in H01(Ω2) may be used as a test class there. (Local weak solutions of a divergence-form operator, Zero-boundary Sobolev space as a norm closure)

[F4]

Smooth-factor Leibniz rule: for η∈Cc∞(Ω) and u∈H1(Ω) the class η2u lies in H1(Ω) and Di(η2u)=η2Diu+2η(Diη)u almost everywhere; a class in H1(Ω) with support in a compact subset of Ω lies in H01 of any open set containing its support. (Weak Leibniz rule with a smooth factor, Compactly supported Sobolev functions extend by zero in every integer order, Zero-boundary Sobolev space as a norm closure, The cutoff difference-quotient commutator estimate).

[F5]

The standard smooth step is smooth with values in [0,1], vanishes on (−∞,0] and equals 1 on [1,∞); the chain rule computes the derivatives of x↦σ(g(x)) as σ′(g(x))Dg(x). (The standard smooth step function, The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a))

[F6]

Cauchy-Schwarz and Young: for real vectors or scalars one has ∣XY∣≤δX2+Y2/(4δ) for every δ>0, and ∫∣FG∣≤∥F∥L2∥G∥L2; the vector estimate ∑i,j∣aijDjuDiv‾∣≤nMa∣Du∣ ∣Dv∣ holds almost everywhere. (Young's inequality for conjugate real exponents, Holder's inequality for integrals, including the endpoint cases, Conjugate exponents, including the endpoint conventions)

Proof

technique · direct
1.1F5givenconstruct

Put s:=(r+R)/2 and define u∗(x):=(s2−∣x−x0∣2)/(s2−r2) and η(x):=σ(u∗(x)) on Rn. Then η is smooth, 0≤η≤1, η=1 on Br(x0), and supp⁡η⊆Bs(x0)‾⊂BR(x0): indeed u∗≥1 on Br(x0) and u∗≤0 off Bs(x0), while s2−r2>0. Thus the support is compactly contained in BR(x0)⋐Ω. Moreover, on the support of σ′∘u∗ one has 0≤u∗≤1, hence ∣x−x0∣≤s, and the chain rule gives ∣Dη(x)∣=∣σ′(u∗(x))∣ ∣Du∗(x)∣≤S 2∣x−x0∣s2−r2≤S 2s(R−r)s/2=4SR−r, because s−r=(R−r)/2 and s+r≥s give s2−r2=(s−r)(s+r)≥(R−r)s/2.

2.1F1F3F4step 1.1

The class v:=η2u lies in H1(Ω) by [F4] and its support is contained in supp⁡η⊆Bs(x0)‾⋐BR(x0)⋐Ω, so v∈H01(BR(x0)) by [F4]; since BR(x0)⋐Ω is bounded, the weak equation of [F3] with the test class v reads a(u,η2u)=∫BR(x0)f η2u‾ dx, both sides finite by the boundedness of the form in [F1].

3.1F2F4F6step 2.1algebra

By the Leibniz rule of [F4], Di(η2u)=η2Diu+2η(Diη)u almost everywhere; substituting this into the definition of the form and splitting the principal part, a(u,η2u)=∫BRη2aijDjuDiu‾ dx+∫BR2η aijDju(Diη)u‾ dx+∫BR(biDiu+cu)η2u‾ dx, and taking real parts in the identity of step 2.1 gives Re⁡∫BRη2aijDjuDiu‾ dx≤2nMa∫BRη∣Dη∣∣Du∣∣u∣+nMb∫BRη2∣Du∣∣u∣+Mc∫BRη2∣u∣2+∫BRη2∣f∣∣u∣, using [F2] for the left side (Re⁡(aijDjuDiu‾)≥θ∣Du∣2) and the coefficient bounds together with [F6] for each remaining term.

4.1F6step 3.1algebra

Estimate the four terms on the right of step 3.1 by Young's inequality with a parameter δ>0: 2nMa∫η∣Dη∣∣Du∣∣u∣≤2nMaδ∫η2∣Du∣2+2nMa4δ∫∣Dη∣2∣u∣2; nMb∫η2∣Du∣∣u∣≤nMbδ∫η2∣Du∣2+nMb4δ∫η2∣u∣2; ∫η2∣f∣∣u∣≤δ∫η2∣f∣2+14δ∫η2∣u∣2; and Mc∫η2∣u∣2 needs no splitting. Choosing δ:=θ/(2(2nMa+nMb)) makes the two ∣Du∣2 coefficients sum to at most θ/2, so the left side of step 3.1 controls the gradient: θ2∫BRη2∣Du∣2 dx≤C1∫BR∣Dη∣2∣u∣2 dx+C2∫BR∣u∣2 dx+C3∫BR∣f∣2 dx with constants C1,C2,C3 depending only on n,θ,Ma,Mb,Mc.

5.1step 1.1step 4.1algebra∎

Since η=1 on Br(x0) and supp⁡η⊆BR(x0), one has ∫Br∣Du∣2≤∫BRη2∣Du∣2, and step 4.1 combined with the gradient bound ∣Dη∣≤4S/(R−r) of step 1.1 gives ∫Br(x0)∣Du∣2 dx≤2θ(C116S2(R−r)2∫BR(x0)∣u∣2 dx+C2∫BR(x0)∣u∣2 dx+C3∫BR(x0)∣f∣2 dx), which is the displayed estimate with C=max⁡{32S2C1/θ, 2C2/θ, 2C3/θ}=C(n,θ,Ma,Mb,Mc), because σ is fixed in advance and S is a universal constant.

Source notes

Simon's Lecture 6, Lemma 1 (printed pp. 58-59) proves the estimate by testing with η2u; Hunter's final step of Theorem 4.27 (printed pp. 112-114) uses the same test function. The explicit (R−r)−2 scale above comes from the rescaled standard bump, whose gradient bound is computed in step 1.1 rather than quoted as a separate lemma, and the constant is uniform over the choice of ball because no quantity depending on x0, r or R enters it except through the displayed powers.

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