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Canonical-link score and Hessian

Statement

Let (Yi)i=1n follow Generalized linear model with explicit conditioning with a common scale a(ϕ)>0, canonical link θi=ηi=xiTβ, and twice differentiable b. For an observed y with fi(yi;ηi,ϕ)>0 for every i,

∇βℓ(β;y,ϕ)=XT(y−μ)a(ϕ),∇β2ℓ(β;y,ϕ)=−XTdiag⁡(b′′(ηi))Xa(ϕ).

Facts & Assumptions

Given: A finite fixed design X, an admissible β, the common-scale canonical-link GLM, and an observed response vector whose component densities are positive at the corresponding canonical parameters.

[F1]

Generalized linear model with explicit conditioning: ηi=xiTβ, the canonical link is θi=ηi, and the common-scale log likelihood is the finite sum of component log densities.

[F2]

The product response law has the product density: the joint density is the product of component densities, so wherever all factors are positive its log likelihood is their sum.

[F3]

Generalized linear model with explicit conditioning: for the canonical link, θi=ηi=τ(μi) and b′(τ(μi))=μi.

[F5]

Matrix differentials obey the sum rule, product rule, and adjoint rule: in the real Frechet sense, d(AB)=dA B+A dB and d(A+B)=dA+dB.

Proof

1.1F1F2F3F4algebra

By [F1] and [F2], ℓ(β;y,ϕ)=∑i{yixiTβ−b(xiTβ)}/a(ϕ)+C(y,ϕ), where C is independent of β. For each coordinate j, the chain rule [F4] gives ∂βjℓ=∑ixij{yi−b′(ηi)}/a(ϕ). By [F3], b′(ηi)=b′(τ(μi))=μi, so these entries assemble as XT(y−μ)/a(ϕ).

2.1F4F5step 1.1algebra∎

Differentiating the coordinate expression in step 1.1 with respect to βk gives ∂βk∂βjℓ=−∑ixijxikb′′(ηi)/a(ϕ) by [F4]. The sum and matrix-product rules [F5] identify these entries with −XTdiag⁡(b′′(ηi))X/a(ϕ).

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