Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

General-link score and Fisher information

Statement

Consider Generalized linear model with explicit conditioning at an admissible finite β with common scale a(ϕ)>0. Assume each ηi↦θi is differentiable, each ηi↦μi is differentiable with μ˙i:=dμi/dηi≠0, Vi:=b′′(θi)>0, the component scores have finite second moments, and the common-support, differentiability, and local integrable derivative-envelope conditions from Explicit exponential-family response contracts hold. Put

wi=μ˙i2a(ϕ)Vi,zi=ηi+yi−μiμ˙i.

For every observed y with fi(yi;θi,ϕ)>0 for each i, the score and expected score outer-product information are

U(β;y,ϕ)=XT(μ˙i(yi−μi)a(ϕ)Vi)i=1n,I(β,ϕ)=XTdiag⁡(wi)X.

In particular, if X has full column rank, then I is positive definite.

Facts & Assumptions

Given: The finite independent-response GLM, common scale, differentiable link and component natural-parameter maps, an observed response vector with positive component densities, fixed common support, local derivative envelopes, and finite second moments in the Statement.

[F1]

Generalized linear model with explicit conditioning: μi=g−1(ηi), ηi=xiTβ, the score is the gradient of the product log likelihood, and I=E[UUT] when finite.

[F2]

Explicit exponential-family response contracts: the component responses are independent, have the displayed common-support response densities, and use the stated product sampling law.

[F3]

Mean and variance from the cumulant function: E[Yi]=μi and Var⁡(Yi)=a(ϕ)Vi under the common-scale restriction.

[F5]

Expectations factor over finite products of independent random variables: for independent real random variables, expectations of products of integrable measurable coordinate functions factor.

Proof

1.1F1F3F4algebra

Differentiate μi=b′(θi) with respect to ηi. The chain rule [F4] gives μ˙i=Vi dθi/dηi, so dθi/dηi=μ˙i/Vi. Differentiating the component log density (yiθi−b(θi))/a(ϕ)+ci(yi,ϕ) therefore gives the scalar score si=μ˙i(yi−μi)/(a(ϕ)Vi). Since ηi=xiTβ, the full score is U=∑ixisi=XT(si)i=1n.

2.1F1F2F3F5step 1.1algebra∎

By [F3], E[si]=0 and E[si2]=μ˙i2/(a(ϕ)Vi)=wi. These second moments are finite by the hypotheses, and ∣si∣≤(1+si2)/2 makes each si integrable. For i≠j, independence and [F5] give E[sisj]=E[si]E[sj]=0. Expanding E[UUT] now leaves only ∑ixixiTwi=XTdiag⁡(wi)X. If v≠0 and X has full column rank, then Xv≠0 and ∑iwi(xiTv)2>0 because each wi>0, proving positive definiteness.

Depends on

Used by

Dependency tree · two levels

36 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources