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A canonical product converges when the -power reciprocal sum converges
Statement
Let be a sequence of nonzero complex numbers with no finite accumulation point, and fix an integer . If
then the canonical product
converges normally on and therefore defines an entire function whose zeros are exactly the points , counted with multiplicity.
Facts & Assumptions
Given: The sequence and the integer .
The factor estimate gives for (The unit-disc estimate for Weierstrass elementary factors).
Canonical products are the fixed-genus Weierstrass products (Weierstrass products, canonical products, and genus).
A normally convergent holomorphic product defines a holomorphic function with exactly the zeros contributed by the finitely many nonzero exceptional factors on each compact set (Normally convergent products define holomorphic functions with the expected zeros).
Proof
Fix a compact disc . Since has no finite accumulation point, , so there is with for ; then on for every .
For and , [F1] gives . Because the reciprocal power series converges, the Weierstrass -test makes convergent.
By [F2], the product is a canonical product, and step 2.1 is exactly the normal-convergence condition on the arbitrary compact disc . Hence [F3] makes the product entire, with zeros exactly at the points and with their multiplicities.
Depends on
Used by
Dependency tree · two levels
13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Elias M. Stein and Rami Shakarchi, Complex Analysis, Ch. 5 Infinite products (standard reference, not scraped)