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Double-centering a finite positive-semidefinite Gram matrix preserves positive semidefiniteness

Statement

Let n≥1 and let K∈Rn×n be symmetric and satisfy aTKa≥0 for every a∈Rn. With Hn=In−n−11n1nT, the centered matrix Kc=HnKHn is symmetric and positive semidefinite. Consequently it has an orthonormal eigenbasis and all its eigenvalues are nonnegative.

Facts & Assumptions

Given: A symmetric positive-semidefinite matrix K∈Rn×n and its centering matrix Hn.

[F1]

Kernel PCA takes a symmetric matrix K with aTKa≥0 for every a and centers it as Kc=HnKHn (Kernel principal component analysis for a finite positive-semidefinite Gram matrix).

[F4]

In an orthonormal basis, a real matrix is self-adjoint exactly when it is symmetric (In an orthonormal basis, self-adjoint means conjugate-transpose symmetry and normal means commuting with the conjugate transpose).

[F5]

Every finite-dimensional real self-adjoint endomorphism has an orthonormal eigenbasis (Real spectral theorem: a self-adjoint endomorphism of a finite-dimensional real inner product space has an orthonormal eigenbasis).

Proof

1.1F1F2algebra

Since KT=K and HnT=Hn by [F1] and [F2], KcT=(HnKHn)T=HnKHn=Kc.

1.2givenF1F2algebra

For every a∈Rn, aTKca=(Hna)TK(Hna)≥0 by the input hypothesis on K. Thus Kc is positive semidefinite.

2.1step 1.1step 1.2F3F4F5∎

The standard coordinate basis is orthonormal for [F3], so [F4] makes the symmetric matrix Kc self-adjoint and [F5] gives an orthonormal eigenbasis. If u is a unit eigenvector with eigenvalue λ, then λ=uTKcu≥0 by step 1.2. Hence every eigenvalue is nonnegative, which makes the stated kernel-PCA eigenprocedure well-defined.

Depends on

Used by

Nothing in the library uses this result yet.

Cited to discharge well-definedness by Kernel principal component analysis for a finite positive-semidefinite Gram matrix.

Dependency tree · two levels

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Sources