Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-09
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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A classical affine variety has a domain coordinate ring, and conversely

Statement

Assume the Axiom of Choice, inherited from the Nullstellensatz route. For an affine algebraic set X, X is a classical affine variety if and only if k[X] is a nonzero integral domain.

Facts & Assumptions

Given: AC, an algebraically closed field k, and an affine algebraic set Xkn.

[F1]

Nonempty irreducible algebraic sets correspond to prime vanishing ideals (Classical affine algebraic sets correspond to radical ideals, and irreducible sets to prime ideals).

[F2]

The coordinate ring is the quotient by the vanishing ideal (The coordinate ring of a classical affine algebraic set).

[F3]

A quotient is a domain exactly when the ideal is prime (R/P is an integral domain if and only if P is a prime ideal).

Proof

technique · direct
1.1

If X is a variety, F1 makes I(X) prime. The polynomial ring is commutative, so F3 applied to I(X) and the quotient in F2 says k[X] is a nonzero domain.

F1F2F3given
2.1

If k[X] is a nonzero domain, F3 makes I(X) prime, and F1 makes X nonempty irreducible. In particular the zero ring k[] is excluded on both sides.

F1F2F3given

Sources

Source comparison: Milne, Algebraic Geometry, v6.10, Proposition 2.27 and §2i, pp. 45–48. Conventions here distinguish arbitrary affine algebraic sets from nonempty irreducible varieties.

Depends on

Used by

Dependency tree · two levels

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Sources