Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-03
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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The bounds ω(G)≤χ(G) and ∣V(G)∣≤χ(G)α(G)

Statement

For every finite simple graph G=(V,E),

ω(G)≤χ(G),∣V∣≤χ(G)α(G).

Both inequalities include the null graph, where all displayed quantities are 0.

Facts & Assumptions

Given: A finite simple graph G=(V,E) and a proper χ(G)-colouring c:V→χ(G).

[L1]

Adjacent vertices receive different colours, and the fibres Cj:=c−1[{j}] are the colour classes (Proper vertex colourings and chromatic number).

[L2]

A clique has all pairs adjacent, an independent set has no adjacent pair, and ω(G) and α(G) are the corresponding maximum cardinalities (Cliques, independent sets, clique number and independence number).

Proof

technique · direct
1.1

If K is a clique, then [L1] makes c∣K injective into the χ(G)-element colour set, so ∣K∣≤χ(G); maximizing over cliques gives ω(G)≤χ(G).

L1L2
1.2

Each colour class Cj is independent, since two vertices in it have the same colour and therefore cannot be adjacent by [L1]; hence ∣Cj∣≤α(G) by [L2].

L1L2
2.1

The colour classes are pairwise disjoint and have union V, so [L3] and step 1.2 give ∣V∣=∑j∈χ(G)∣Cj∣≤∑j∈χ(G)α(G)=χ(G)α(G).

step 1.2L3
3.1

Steps 1.1 and 2.1 prove the two claimed bounds, including the empty family of colour classes when V=∅.

step 1.1step 2.1∎

Depends on

Used by

Dependency tree · two levels

24 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources